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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory,sci.logic
Subject: Re: A computable function that reports on the behavior of its actual
 self is not allowed
Date: Mon, 13 May 2024 20:30:14 -0400
Organization: i2pn2 (i2pn.org)
Message-ID: <v1ubam$v37v$8@i2pn2.org>
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On 5/13/24 2:20 PM, olcott wrote:
> On 5/12/2024 7:39 PM, Richard Damon wrote:
>> On 5/12/24 8:12 PM, olcott wrote:
>>> On 5/12/2024 6:57 PM, Richard Damon wrote:
>>>> On 5/12/24 7:14 PM, olcott wrote:
>>>>> On 5/12/2024 5:40 PM, Richard Damon wrote:
>>>>>> On 5/12/24 6:21 PM, olcott wrote:
>>>>>>> On 5/12/2024 4:40 PM, Richard Damon wrote:
>>>>>>>> On 5/12/24 5:18 PM, olcott wrote:
>>>>>>>>> On 5/12/2024 2:27 PM, olcott wrote:
>>>>>
>>>>>>>>>> Computable functions are the basic objects of study in 
>>>>>>>>>> computability
>>>>>>>>>> theory. Computable functions are the formalized analogue of the
>>>>>>>>>> intuitive notion of algorithms, in the sense that a function is
>>>>>>>>>> computable if there exists an algorithm that can do the job of 
>>>>>>>>>> the
>>>>>>>>>> function, i.e. given an input of the function domain it can 
>>>>>>>>>> return the
>>>>>>>>>> corresponding output. 
>>>>>
>>>>>>>>>> https://en.wikipedia.org/wiki/Computable_function
>>>>>>>>>>
>>>>>>>>>> A computable function that reports on the behavior of its actual
>>>>>>>>>> self (or reports on the behavior of its caller) is not allowed.
>>>>>>>>>>
>>>>>>>>>> A decider must halt whereas simulating a pathological input
>>>>>>>>>> that would never halt unless aborted can only halt by aborting.
>>>>>>>>>>
>>>>>>>>>> This causes the direct execution of this input after it has 
>>>>>>>>>> been aborted
>>>>>>>>>> to have different behavior than the simulated input that 
>>>>>>>>>> cannot possibly
>>>>>>>>>> stop running unless aborted.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> *MORE PRECISE WORDING* (this may take a few more rewrites)
>>>>>>>>> When Ĥ is applied to ⟨Ĥ⟩
>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>>>>>>>>>
>>>>>>>>> It is a verified fact that the directly executed Ĥ ⟨Ĥ⟩ cannot 
>>>>>>>>> possibly
>>>>>>>>> stop running unless simulating partial halt decider embedded_H 
>>>>>>>>> aborts
>>>>>>>>> its simulation of its input.
>>>>>>>>
>>>>>>>> But since embedded_H implements a specific algorithm, either it 
>>>>>>>> will or it won't. "unless" is a meaningless word here, it 
>>>>>>>> implies a case that can't happen.
>>>>>>>>
>>>>>>>> We can look at the two possible cases.
>>>>>>>>
>>>>>>>> First, if embedded_H doesn't ever abort its simulation, then, as 
>>>>>>>> you have desceribed, THAT embedded_H creates a H^ that will 
>>>>>>>> never halt, but the H that was based on will also never abort 
>>>>>>>> its simulation (or you lied that embedded_H is the needed copy 
>>>>>>>> of H) and thus never answer and fail to be a decider.
>>>>>>>>
>>>>>>>
>>>>>>> It can answer without halting by transitioning to its own internal
>>>>>>> non-final state of embedded_H.qn without ever reaching Ĥ.qn. Every
>>>>>>> simulated instance of embedded_H would do this same thing and then
>>>>>>> continue simulating its input.
>>>>>> So, you just don't understand how algorithms work, and how 
>>>>>> compuations are DEFINED.
>>>>>>
>>>>>>
>>>>>> If you want to try to define a new system of compuation that 
>>>>>> allows giving answer without the algorithm ending, but still 
>>>>>> allows all the composition operations that are included in 
>>>>>> computation theory, go ahead and try.
>>>>>>
>>>>>> You then need to show that it is Turing Complete, which means that 
>>>>>> you can't outlaw any computation allowed in a Turing Machine, like 
>>>>>> H^.
>>>>>>
>>>>>
>>>>> *It <is> a way for embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ to get the correct answer*
>>>>> *It <is> a way for embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ to get the correct answer*
>>>>> *It <is> a way for embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ to get the correct answer*
>>>>
>>>> Nope.
>>>>
>>>> Claiming to do something that isn't the way defined doesn't make it 
>>>> work.
>>>>
>>>
>>> It is not a halt decider. It is not even a termination analyzer.
>>> It <is> an huge improvement over both YES and NO from H are the
>>> wrong answer.  NO from H IS THE CORRECT ANSWER.
>>
>> It isn't even a "program" per the term-of-the-art, since it generates 
>> and answer without ending, thus your "proof" is based on lies.
>>
> 
> I have no idea what you are basing this on, a "program"
> is not any term-of-the-art of the theory of computation.

Then why is one phrasing of the Halting Problem about the decider 
answering about the "program" given to it?

I guess you just don't understand what the terms mean.

> 
> It is well known in the field that some Turing Machines
> never halt, so it certainly can be a Turing machine.

Yes, but it doesn't ANSWER.

Remember the definition of a decider,


> 
> You are certainly correct that it is not a computable
> function.

So, you AGREE that you 20 year quest to show that Turing was WRONG about 
Halting not being a computable function, as we can not build an always 
correct Halt Decider?

> 
> We can say that H is proven to "know" the correct halt
> status, yet cannot "say" the correct halt status in the
> conventional way.

But that isn't what Computation Theory is about.

> 
> Objectively this does seem to be a significant breakthrough
> over both YES and NO are the wrong answer from H. I don't
> think that you can provide any correct reasoning to the contrary.

Nope.

And Yes and No are not both wrong, Which ever answer that H gives is 
wrong, and the other is right.

You don't seem to understand that a given H will ALWAYS give the same 
answer to the same input, and thus only one answer needs to be wrong.


> 
> *RHETORIC COUNTS AS ZERO REASONING*
> *RHETORIC COUNTS AS ZERO REASONING*
> *RHETORIC COUNTS AS ZERO REASONING*

Right, like what you use. Note, I intersperse my "Rhetoric" with facts, 
unlike you.

> 
>>>
>>>> That it like claiming you can make you cat bark, by trying to call 
>>>> your dog a cat.
>>>>
>>>>>
>>>>> Every prior work that I have ever seen and probably every prior
>>>>> work that exists essentially concludes that both YES and NO are the
>>>>> wrong answer for H to provide for every H/D pair where H and D have
>>>>> the HP pathological relationship.
>>>>
>>>> Which ever answer H gives, will be wrong.
>>>>
>>>
>>> I JUST PROVED OTHERWISE.
>>> YES IS THE CORRECT ANSWER AND AS LONG AS H PROVIDES
>>> THIS ANSWER WITHOUT STOPPING NOTHING CONTRADICTS IT.
>>>
>>
>> Where?
>>
>> You claimed the equivalent of a cat being a 10 story office building.
>>
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