Deutsch English Français Italiano |
<v1vrm6$7577$2@dont-email.me> View for Bookmarking (what is this?) Look up another Usenet article |
Path: ...!3.eu.feeder.erje.net!feeder.erje.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: olcott <polcott333@gmail.com> Newsgroups: comp.theory Subject: Re: Termination analyzer defined ---RICHARD IS WRONG !!! Date: Tue, 14 May 2024 09:15:34 -0500 Organization: A noiseless patient Spider Lines: 40 Message-ID: <v1vrm6$7577$2@dont-email.me> References: <v1me7i$1l6ut$1@dont-email.me> <v1nec4$1vb8i$1@dont-email.me> <v1o6p5$24f4c$2@dont-email.me> <v1pvj0$2knal$1@dont-email.me> <v1qi01$2on4q$2@dont-email.me> <v1qn4o$2pts6$1@dont-email.me> <v1qt92$2rdui$1@dont-email.me> <v1sl6o$3cg5n$1@dont-email.me> <v1tktb$3jv6d$1@dont-email.me> <v1vb6j$3ccc$1@dont-email.me> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Tue, 14 May 2024 16:15:34 +0200 (CEST) Injection-Info: dont-email.me; posting-host="e9b15de5cbd4b611ca4438a3f5fabf94"; logging-data="234727"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX18OLZ91ITdUawkPWIkSvCKL" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:DRfMhBeLfJBVv6JLh7gQybzZ7Kc= In-Reply-To: <v1vb6j$3ccc$1@dont-email.me> Content-Language: en-US Bytes: 2995 On 5/14/2024 4:34 AM, Mikko wrote: > On 2024-05-13 18:07:37 +0000, Jeff Barnett said: > >> On 5/13/2024 3:06 AM, Mikko wrote: >> >>> Anyway, if an analyzer can never tell whether a program terminates >>> with every possible input then it is not a termination analyzer. >> >> I don't think the above is true in the way you meant it. Recall that >> the collection of all Turing machines with blank input tapes is the >> same set of computations as the collection with arbitrary input tapes. >> It's always possible to take any specific machine, T, and initial >> tape, I, and produce machine T' with blank initial input tape that is >> equivalent: T' initially writes I on its tape (say one character >> output per state in sequence) then continues with the set of states >> that comprises T. >> >> So it is obvious that a termination analyzer (AKA a halt decider) >> restricted to blank tape problems will do quite nicely and it is also >> quite obvious that no such entity exists. > > You only discuss halting decisions with specific inputs. THerefore you say > nothing about termination analyzers and don't show any mistake in my > comment. > When Ĥ is applied to ⟨Ĥ⟩ Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞ Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn *My focus is even more narrow than that* I only need to show that Linz embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ does correctly determine the halt status of its input and the halting problem proofs are refuted. -- Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius hits a target no one else can see." Arthur Schopenhauer