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From: olcott <polcott333@gmail.com>
Newsgroups: sci.logic,comp.theory
Subject: Re: True on the basis of meaning --- Good job Richard ! ---Socratic
 method
Date: Mon, 20 May 2024 12:48:40 -0500
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On 5/20/2024 2:55 AM, Mikko wrote:
> On 2024-05-19 14:15:51 +0000, olcott said:
> 
>> On 5/19/2024 9:03 AM, Mikko wrote:
>>> On 2024-05-19 13:41:56 +0000, olcott said:
>>>
>>>> On 5/19/2024 6:55 AM, Richard Damon wrote:
>>>>> On 5/18/24 11:47 PM, olcott wrote:
>>>>>> On 5/18/2024 6:04 PM, Richard Damon wrote:
>>>>>>> On 5/18/24 6:47 PM, olcott wrote:
>>>>>>>> On 5/18/2024 5:22 PM, Richard Damon wrote:
>>>>>>>>> On 5/18/24 4:00 PM, olcott wrote:
>>>>>>>>>> On 5/18/2024 2:57 PM, Richard Damon wrote:
>>>>>>>>>>> On 5/18/24 3:46 PM, olcott wrote:
>>>>>>>>>>>> On 5/18/2024 12:38 PM, Richard Damon wrote:
>>>>>>>>>>>>> On 5/18/24 1:26 PM, olcott wrote:
>>>>>>>>>>>>>> On 5/18/2024 11:56 AM, Richard Damon wrote:
>>>>>>>>>>>>>>> On 5/18/24 12:48 PM, olcott wrote:
>>>>>>>>>>>>>>>> On 5/18/2024 9:32 AM, Richard Damon wrote:
>>>>>>>>>>>>>>>>> On 5/18/24 10:15 AM, olcott wrote:
>>>>>>>>>>>>>>>>>> On 5/18/2024 7:43 AM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>> No, your system contradicts itself.
>>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>>> You have never shown this.
>>>>>>>>>>>>>>>>>> The most you have shown is a lack of understanding of the
>>>>>>>>>>>>>>>>>> Truth Teller Paradox.
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>> No, I have, but you don't understand the proof, it 
>>>>>>>>>>>>>>>>> seems because you don't know what a "Truth Predicate" 
>>>>>>>>>>>>>>>>> has been defined to be.
>>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>>> My True(L,x) predicate is defined to return true or 
>>>>>>>>>>>>>>>> false for every
>>>>>>>>>>>>>>>> finite string x on the basis of the existence of a 
>>>>>>>>>>>>>>>> sequence of truth
>>>>>>>>>>>>>>>> preserving operations that derive x from
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>>> And thus, When True(L, p) established a sequence of truth 
>>>>>>>>>>>>>>> preserving operations eminationg from ~True(L, p) by 
>>>>>>>>>>>>>>> returning false, it contradicts itself. The problem is 
>>>>>>>>>>>>>>> that True, in making an answer of false, has asserted 
>>>>>>>>>>>>>>> that such a sequence exists.
>>>>>>>>>>>>>>>
>>>>>>>>>>>>>> On 5/13/2024 9:31 PM, Richard Damon wrote:
>>>>>>>>>>>>>>  > On 5/13/24 10:03 PM, olcott wrote:
>>>>>>>>>>>>>>  >> On 5/13/2024 7:29 PM, Richard Damon wrote:
>>>>>>>>>>>>>>  >>>
>>>>>>>>>>>>>>  >>> Remember, p defined as ~True(L, p) ...
>>>>>>>>>>>>>>  >>
>>>>>>>>>>>>>>  >> Can a sequence of true preserving operations applied
>>>>>>>>>>>>>>  >> to expressions that are stipulated to be true derive p?
>>>>>>>>>>>>>>  > No, so True(L, p) is false
>>>>>>>>>>>>>>  >>
>>>>>>>>>>>>>>  >> Can a sequence of true preserving operations applied
>>>>>>>>>>>>>>  >> to expressions that are stipulated to be true derive ~p?
>>>>>>>>>>>>>>  >
>>>>>>>>>>>>>>  > No, so False(L, p) is false,
>>>>>>>>>>>>>>  >
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> *To help you concentrate I repeated this*
>>>>>>>>>>>>>> The Liar Paradox and your formalized Liar Paradox both
>>>>>>>>>>>>>> contradict themselves that is why they must be screened
>>>>>>>>>>>>>> out as type mismatch error non-truth-bearers *BEFORE THAT 
>>>>>>>>>>>>>> OCCURS*
>>>>>>>>>>>>>
>>>>>>>>>>>>> And the Truth Predicate isn't allowed to "filter" out 
>>>>>>>>>>>>> expressions.
>>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> YOU ALREADY KNOW THAT IT DOESN'T
>>>>>>>>>>>> WE HAVE BEEN OVER THIS AGAIN AND AGAIN
>>>>>>>>>>>> THE FORMAL SYSTEM USES THE TRUE AND FALSE PREDICATE
>>>>>>>>>>>> TO FILTER OUT TYPE MISMATCH ERROR
>>>>>>>>>>>>
>>>>>>>>>>>> The first thing that the formal system does with any
>>>>>>>>>>>> arbitrary finite string input is see if it is a Truth-bearer:
>>>>>>>>>>>> Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>>>>>
>>>>>>>>>>> No, we can ask True(L, x) for any expression x and get an 
>>>>>>>>>>> answer.
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> The system is designed so you can ask this, yet non-truth-bearers
>>>>>>>>>> are rejected before True(L, x) is allowed to be called.
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> Not allowed.
>>>>>>>>>
>>>>>>>>
>>>>>>>> My True(L,x) predicate is defined to return true or false for every
>>>>>>>> finite string x on the basis of the existence of a sequence of 
>>>>>>>> truth
>>>>>>>> preserving operations that derive x from
>>>>>>>>
>>>>>>>> A set of finite string semantic meanings that form an accurate
>>>>>>>> verbal model of the general knowledge of the actual world that
>>>>>>>> form a finite set of finite strings that are stipulated to have
>>>>>>>> the semantic value of Boolean true.
>>>>>>>>
>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>>
>>>>>>>>
>>>>>>>
>>>>>>> So, for a statement x to be false, it says that there must be a 
>>>>>>> sequence of truth perserving operations that derive ~x from, right?
>>>>>>>
>>>>>> Yes we must build from mutual agreement, good.
>>>>>>
>>>>>>> So do you still say that for p defined in L as ~True(L, p) that 
>>>>>>> your definition will say that True(L, p) will return false?
>>>>>>>
>>>>>>
>>>>>> It is the perfectly isomorphic to this:
>>>>>> True(English, "This sentence is not true")
>>>>>>
>>>>>
>>>>>
>>>>> Nope, Because "This sentece is not true" can be a non-truth-bearer, 
>>>>> but by its definition, True(L, x) can not.
>>>>>
>>>>
>>>> True(L,x) is always a truth bearer.
>>>> when x is defined as True(L,x) then x is not a truth bearer.
>>>
>>> When x is defined as True(L,x) then x is what True(L,x) is,
>>> in this case a truth bearer.
> 
>> This is known as the Truth Teller Paradox
> 
> Doesn't matter. But ir you say that "x is not a truth bearer" then,
> by a truth preserving transformation, you imply that True(L,x) is

True(English, "a cat is an animal) is true
LP := ~True(L, LP) expands to ~True(~True(~True(~True(...))))
TT := True(L, TT) expands to True(True(True(True(...))))

> not a truth bearer. As you already said that "True(L,x)" is always
> a truth bearer, you imply, by another truth preeserving transformation,
> that something both is and is not a truth bearer.
> 

*Not at all*
*Prolog sees the same infinite recursion and rejects it*

?- LP = not(true_(LP)).
LP = not(true(LP)).
?- unify_with_occurs_check(LP, not(true(LP))).
false.

?- TT = true(TT).
TT = true(TT).
?- unify_with_occurs_check(TT, true(TT)).
false.

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