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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: sci.logic
Subject: Re: True on the basis of meaning --- Good job Richard ! ---Socratic method (agreement)
Date: Fri, 24 May 2024 12:25:33 +0300
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On 2024-05-23 13:23:54 +0000, olcott said:

> On 5/23/2024 2:54 AM, Mikko wrote:
>> On 2024-05-22 19:52:59 +0000, olcott said:
>> 
>>> On 5/22/2024 11:58 AM, Mikko wrote:
>>>> On 2024-05-22 15:55:39 +0000, olcott said:
>>>> 
>>>>> On 5/22/2024 2:57 AM, Mikko wrote:
>>>>>> On 2024-05-21 14:36:29 +0000, olcott said:
>>>>>> 
>>>>>>> On 5/21/2024 3:05 AM, Mikko wrote:
>>>>>>>> On 2024-05-20 17:48:40 +0000, olcott said:
>>>>>>>> 
>>>>>>>>> On 5/20/2024 2:55 AM, Mikko wrote:
>>>>>>>>>> On 2024-05-19 14:15:51 +0000, olcott said:
>>>>>>>>>> 
>>>>>>>>>>> On 5/19/2024 9:03 AM, Mikko wrote:
>>>>>>>>>>>> On 2024-05-19 13:41:56 +0000, olcott said:
>>>>>>>>>>>> 
>>>>>>>>>>>>> On 5/19/2024 6:55 AM, Richard Damon wrote:
>>>>>>>>>>>>>> On 5/18/24 11:47 PM, olcott wrote:
>>>>>>>>>>>>>>> On 5/18/2024 6:04 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>> On 5/18/24 6:47 PM, olcott wrote:
>>>>>>>>>>>>>>>>> On 5/18/2024 5:22 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>> On 5/18/24 4:00 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>> On 5/18/2024 2:57 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>> On 5/18/24 3:46 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>> On 5/18/2024 12:38 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>> On 5/18/24 1:26 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>> On 5/18/2024 11:56 AM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>> On 5/18/24 12:48 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>>>> On 5/18/2024 9:32 AM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>> On 5/18/24 10:15 AM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>> On 5/18/2024 7:43 AM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>>>>>> No, your system contradicts itself.
>>>>>>>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>>>>>>>> You have never shown this.
>>>>>>>>>>>>>>>>>>>>>>>>>>> The most you have shown is a lack of understanding of the
>>>>>>>>>>>>>>>>>>>>>>>>>>> Truth Teller Paradox.
>>>>>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>>>>>>> No, I have, but you don't understand the proof, it seems because you 
>>>>>>>>>>>>>>>>>>>>>>>>>> don't know what a "Truth Predicate" has been defined to be.
>>>>>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>>>>>> My True(L,x) predicate is defined to return true or false for every
>>>>>>>>>>>>>>>>>>>>>>>>> finite string x on the basis of the existence of a sequence of truth
>>>>>>>>>>>>>>>>>>>>>>>>> preserving operations that derive x from
>>>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>>>>> And thus, When True(L, p) established a sequence of truth preserving 
>>>>>>>>>>>>>>>>>>>>>>>> operations eminationg from ~True(L, p) by returning false, it 
>>>>>>>>>>>>>>>>>>>>>>>> contradicts itself. The problem is that True, in making an answer of 
>>>>>>>>>>>>>>>>>>>>>>>> false, has asserted that such a sequence exists.
>>>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>>>> On 5/13/2024 9:31 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>  > On 5/13/24 10:03 PM, olcott wrote:
>>>>>>>>>>>>>>>>>>>>>>>  >> On 5/13/2024 7:29 PM, Richard Damon wrote:
>>>>>>>>>>>>>>>>>>>>>>>  >>>
>>>>>>>>>>>>>>>>>>>>>>>  >>> Remember, p defined as ~True(L, p) ...
>>>>>>>>>>>>>>>>>>>>>>>  >>
>>>>>>>>>>>>>>>>>>>>>>>  >> Can a sequence of true preserving operations applied
>>>>>>>>>>>>>>>>>>>>>>>  >> to expressions that are stipulated to be true derive p?
>>>>>>>>>>>>>>>>>>>>>>>  > No, so True(L, p) is false
>>>>>>>>>>>>>>>>>>>>>>>  >>
>>>>>>>>>>>>>>>>>>>>>>>  >> Can a sequence of true preserving operations applied
>>>>>>>>>>>>>>>>>>>>>>>  >> to expressions that are stipulated to be true derive ~p?
>>>>>>>>>>>>>>>>>>>>>>>  >
>>>>>>>>>>>>>>>>>>>>>>>  > No, so False(L, p) is false,
>>>>>>>>>>>>>>>>>>>>>>>  >
>>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>>>> *To help you concentrate I repeated this*
>>>>>>>>>>>>>>>>>>>>>>> The Liar Paradox and your formalized Liar Paradox both
>>>>>>>>>>>>>>>>>>>>>>> contradict themselves that is why they must be screened
>>>>>>>>>>>>>>>>>>>>>>> out as type mismatch error non-truth-bearers *BEFORE THAT OCCURS*
>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>>> And the Truth Predicate isn't allowed to "filter" out expressions.
>>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>> YOU ALREADY KNOW THAT IT DOESN'T
>>>>>>>>>>>>>>>>>>>>> WE HAVE BEEN OVER THIS AGAIN AND AGAIN
>>>>>>>>>>>>>>>>>>>>> THE FORMAL SYSTEM USES THE TRUE AND FALSE PREDICATE
>>>>>>>>>>>>>>>>>>>>> TO FILTER OUT TYPE MISMATCH ERROR
>>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>>> The first thing that the formal system does with any
>>>>>>>>>>>>>>>>>>>>> arbitrary finite string input is see if it is a Truth-bearer:
>>>>>>>>>>>>>>>>>>>>> Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>>> No, we can ask True(L, x) for any expression x and get an answer.
>>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>> The system is designed so you can ask this, yet non-truth-bearers
>>>>>>>>>>>>>>>>>>> are rejected before True(L, x) is allowed to be called.
>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>>> Not allowed.
>>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>> My True(L,x) predicate is defined to return true or false for every
>>>>>>>>>>>>>>>>> finite string x on the basis of the existence of a sequence of truth
>>>>>>>>>>>>>>>>> preserving operations that derive x from
>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>> A set of finite string semantic meanings that form an accurate
>>>>>>>>>>>>>>>>> verbal model of the general knowledge of the actual world that
>>>>>>>>>>>>>>>>> form a finite set of finite strings that are stipulated to have
>>>>>>>>>>>>>>>>> the semantic value of Boolean true.
>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>>>>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>>>>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>>>>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>>>>>>>>>>> *This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>> So, for a statement x to be false, it says that there must be a 
>>>>>>>>>>>>>>>> sequence of truth perserving operations that derive ~x from, right?
>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>> Yes we must build from mutual agreement, good.
>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>>> So do you still say that for p defined in L as ~True(L, p) that your 
>>>>>>>>>>>>>>>> definition will say that True(L, p) will return false?
>>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>>> It is the perfectly isomorphic to this:
>>>>>>>>>>>>>>> True(English, "This sentence is not true")
>>>>>>>>>>>>>>> 
>>>>>>>>>>>>>> 
>>>>>>>>>>>>>> 
>>>>>>>>>>>>>> Nope, Because "This sentece is not true" can be a non-truth-bearer, but 
>>>>>>>>>>>>>> by its definition, True(L, x) can not.
>>>>>>>>>>>>>> 
>>>>>>>>>>>>> 
>>>>>>>>>>>>> True(L,x) is always a truth bearer.
>>>>>>>>>>>>> when x is defined as True(L,x) then x is not a truth bearer.
>>>>>>>>>>>> 
>>>>>>>>>>>> When x is defined as True(L,x) then x is what True(L,x) is,
>>>>>>>>>>>> in this case a truth bearer.
>>>>>>>>>> 
>>>>>>>>>>> This is known as the Truth Teller Paradox
>>>>>>>>>> 
>>>>>>>>>> Doesn't matter. But ir you say that "x is not a truth bearer" then,
>>>>>>>>>> by a truth preserving transformation, you imply that True(L,x) is
>>>>>>>>> 
>>>>>>>>> True(English, "a cat is an animal) is true
>>>>>>>>> LP := ~True(L, LP) expands to ~True(~True(~True(~True(...))))
>>>>>>>> 
>>>>>>>> No, it doesn't. It is a syntax error to have the same symbol on
>>>>>>>> both sides ":=" so the expansion is not justified.
>>>>>>> 
>>>>>>> ϕ(x) there is a sentence ψ such that S ⊢ ψ ↔ ϕ⟨ψ⟩.
>>>>>>> *The sentence ψ is of course not self-referential in a strict sense*,
>>>>>>> but mathematically it behaves like one.
>>>>>>> https://plato.stanford.edu/entries/self-reference/#ConSemPar
>>>>>> 
>>>>>> Your quote omitted important details. One is that the claim is not
>>>>>> true about every theory but is about first order arithmetic and its
>>>>>> extension. Another one is that ϕ(x) is that the claim is about
>>>>>> every formula ϕ(x).
>>>>>> 
>>>>> 
>>>>> *The whole article is about self-reference*
>>>>> The ONLY detail that I am referring to is that it is conventional to 
>>>>> formalize self-reference incorrectly.
>>>>> 
>>>>> *Richard and both fixed that*
>>>>> 
>>>>> On 5/13/2024 9:31 PM, Richard Damon wrote:
>>>>>  > On 5/13/24 10:03 PM, olcott wrote:
>>>>>  >> On 5/13/2024 7:29 PM, Richard Damon wrote:
>>>>>  >>>
>>>>>  >>> Remember, p defined as ~True(L, p) ...
>>>>> 
>>>>> x := y means x is defined to be another name for y
>>>> 
>>>> Another name for the meaning of y. Therefore any pair of sentences that
>>>> are otherwise equal but one contains x where rhe other contains y is a pair
>>>> of equally true sentences. For example, if p defined as ~True(L, ⟨p⟩)
>>> 
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