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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic
Subject: =?UTF-8?Q?Re=3A_A_simulating_halt_decider_applied_to_the_The_Peter_?=
 =?UTF-8?Q?Linz_Turing_Machine_description_=E2=9F=A8=C4=A4=E2=9F=A9?=
Date: Sun, 26 May 2024 21:53:58 -0500
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On 5/26/2024 9:30 PM, Richard Damon wrote:
> On 5/26/24 10:06 PM, olcott wrote:
>> When Ĥ is applied to ⟨Ĥ⟩
>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>>
>>   Ĥ copies its own Turing machine description: ⟨Ĥ⟩
>>   then invokes embedded_H that simulates ⟨Ĥ⟩ with ⟨Ĥ⟩ as input.
>>
>> It is an easily verified fact that ⟨Ĥ⟩ ⟨Ĥ⟩ correctly simulated by
>> embedded_H cannot possibly reach its own simulated final state of
>> ⟨Ĥ.qn⟩ in any finite sequence of steps such as Googolplex ^ Googolplex
>> number of steps. https://en.wikipedia.org/wiki/Googolplex
> 
> So, it can verify that if H / embedded_H was programmed not to halt it 
> simulation, then the H^ built on that H will be non-halting, but that 
> doesn't say anything about the DIFFERENT H^ built on an H that does 
> abort its simulation and returns 0.
> 

You really do have an actual problem paying attention.
It is not a mere trollish ruse. I poured engine oil
into my power steering fluid Friday night so I can relate.

As far as paying attention to words that have been written
I read and reread many times until I am sure that I get it.
Even then I get it wrong once in a while.

When embedded_H correctly simulates a Googolplex ^ Googolplex steps
of ⟨Ĥ⟩ ⟨Ĥ⟩ then embedded_H halts.

⟨Ĥ⟩ ⟨Ĥ⟩ correctly simulated by embedded_H cannot possibly reach its
own simulated final state of ⟨Ĥ.qn⟩ in any finite number of steps.



-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer