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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory
Subject: Re: Two dozen people were simply wrong --- Try to prove otherwise
Date: Thu, 30 May 2024 21:37:23 -0400
Organization: i2pn2 (i2pn.org)
Message-ID: <v3b9kj$2im02$1@i2pn2.org>
References: <v3501h$lpnh$1@dont-email.me> <v362eu$2d367$3@i2pn2.org>
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<v37bpa$15n0b$1@dont-email.me> <v37i9p$lls$1@news.muc.de>
<87y17smqnq.fsf@bsb.me.uk> <v37sap$18mfo$1@dont-email.me>
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On 5/30/24 9:31 AM, olcott wrote:
> On 5/30/2024 2:40 AM, Mikko wrote:
>> On 2024-05-30 01:15:21 +0000, olcott said:
>>
>>> On 5/29/2024 8:07 PM, Richard Damon wrote:
>>>> On 5/29/24 8:59 PM, olcott wrote:
>>>>> On 5/29/2024 7:48 PM, Richard Damon wrote:
>>>>>> On 5/29/24 8:17 PM, olcott wrote:
>>>>>>> On 5/29/2024 7:09 PM, Richard Damon wrote:
>>>>>>>> On 5/29/24 7:57 PM, olcott wrote:
>>>>>>>>> On 5/29/2024 6:47 PM, Richard Damon wrote:
>>>>>>>>>> On 5/29/24 2:31 PM, olcott wrote:
>>>>>>>>>>> On 5/29/2024 1:14 PM, Ben Bacarisse wrote:
>>>>>>>>>>>> Alan Mackenzie <acm@muc.de> writes:
>>>>>>>>>>>>
>>>>>>>>>>>>> How about a bit of respect? Mike specifically asked you
>>>>>>>>>>>>> not to cite his
>>>>>>>>>>>>> name as a back up for your points. Why do you keep doing it?
>>>>>>>>>>>>
>>>>>>>>>>>> He does it to try to rope more people in. It's the same
>>>>>>>>>>>> ploy as
>>>>>>>>>>>> insulting people by name. It's hard to ignore being
>>>>>>>>>>>> maligned in public
>>>>>>>>>>>> by a fool.
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> *Thanks for validating my simplified encoding of the Linz*
>>>>>>>>>>>
>>>>>>>>>>> When Ĥ is applied to ⟨Ĥ⟩
>>>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
>>>>>>>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>>>>>>>>>>>
>>>>>>>>>>> I really did believe that Ben Bacarisse was lying when I said
>>>>>>>>>>> it.
>>>>>>>>>>>
>>>>>>>>>>> At the time I was talking about the easily verified fact of
>>>>>>>>>>> the actual
>>>>>>>>>>> execution trace of fully operational code and everyone was
>>>>>>>>>>> denying the
>>>>>>>>>>> easily verified facts.
>>>>>>>>>>>
>>>>>>>>>>> typedef int (*ptr)(); // ptr is pointer to int function in C
>>>>>>>>>>> 00 int H(ptr p, ptr i);
>>>>>>>>>>> 01 int D(ptr p)
>>>>>>>>>>> 02 {
>>>>>>>>>>> 03 int Halt_Status = H(p, p);
>>>>>>>>>>> 04 if (Halt_Status)
>>>>>>>>>>> 05 HERE: goto HERE;
>>>>>>>>>>> 06 return Halt_Status;
>>>>>>>>>>> 07 }
>>>>>>>>>>> 08
>>>>>>>>>>> 09 int main()
>>>>>>>>>>> 10 {
>>>>>>>>>>> 11 H(D,D);
>>>>>>>>>>> 12 return 0;
>>>>>>>>>>> 13 }
>>>>>>>>>>>
>>>>>>>>>>> It turns out that two dozen people are easily proven wrong when
>>>>>>>>>>> they claimed that the correct simulation of the input to H(D,D)
>>>>>>>>>>> is the behavior of int main() { D(D); }
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> How is that?
>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>>> When D is correctly simulated by H using an x86 emulator the
>>>>>>>>>>> only
>>>>>>>>>>> way that the emulated D can reach its own emulated final state
>>>>>>>>>>> at line 06 and halt is
>>>>>>>>>>> (a) The x86 machine code of D is emulated incorrectly
>>>>>>>>>>> (b) The x86 machine code of D is emulated in the wrong order
>>>>>>>>>>>
>>>>>>>>>>
>>>>>>>>>> Which isn't a "Correct Simulation" by the definition that
>>>>>>>>>> allow the relating of a "Simulation" to the behavior of an input.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> Right the execution trace of D simulated by pure function H using
>>>>>>>>> an x86 emulator must show that D cannot possibly reach its own
>>>>>>>>> simulated final state and halt or the simulation of the machine
>>>>>>>>> language of D is incorrect or in the wrong order.
>>>>>>>>
>>>>>>>> So, you aren't going to resolve the question but just keep up
>>>>>>>> with your contradiction that H is simulating a template (that
>>>>>>>> doesn't HAVE any instrucitons of H in it) but also DOES simulate
>>>>>>>> those non-existance instructions by LYING about what it does and
>>>>>>>> simulating a SPECIFIC instance that it LIES behaves just like
>>>>>>>> DIFFERENT specific instatces.
>>>>>>>
>>>>>>> I will give you the benefit of the doubt and call that an honest
>>>>>>> misunderstanding. I have much more empathy for you now that I found
>>>>>>> that Linz really did say words that you could construe as you did.
>>>>>>>
>>>>>>> The infinite set of every H/D pair specified by the template
>>>>>>> where D is correctly simulated by pure simulator H or pure function
>>>>>>> H never has any D reach its own simulated final state and halt.
>>>>>>
>>>>>> But the question ISN'T about the SIMULATED D, but about the
>>>>>> behavior of the actual PROGRAM/MACHINE D
>>>>>>
>>>>>> This seems to be your blind spot.
>>>>>
>>>>> ∃H ∈ Turing_Machines
>>>>> ∀x ∈ Turing_Machines_Descriptions
>>>>> ∀y ∈ Finite_Strings
>>>>> such that H(x,y) = Halts(x,y)
>>>>>
>>>>> Not really the above formalization does not can cannot
>>>>> specify Turing Machines as the input to any decider H.
>>>>>
>>>>
>>>> Then what is x representing?
>>>
>>> x <is> a finite string Turing machine description that SPECIFIES
>>> behavior. The term: "representing" is inaccurate.
>>
>> No, x is a description of the Turing machine that specifies the behaviour
>> that H is required to report.
>
> That is what I said.
Note, the string doesn't DIRECTLY specify behavior, but only indirectly
as a description/representation of the Turing Mach
>
>> The maning of x is that there is a universal
>> Turing machine that, when given x and y, simulates what the described
>> Turing machine does when given y.
>
> Yes that is also correct.
>
> When Ĥ is applied to ⟨Ĥ⟩
> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>
> When embedded_H is a UTM then it never halts.
But it isn't unless H is also a UTM, and then H never returns.
You like to keep returning to that deception.
>
> When embedded_H is a simulating halt decider then its correctly
> simulated input never reaches its own simulated final state of
> ⟨Ĥ.qn⟩ and halts. H itself does halt and correctly rejects its
> input as non-halting.
Except that isn't what the question is, the question is what the actual
behavior of the machine described, or equivalently, the simulation by a
REAL UTM (one that never stops till done).
As has been shown, H / embedded_H can't be that and answer, so either
your embedded_H needs to answer about a simulation done by a different
machine (which seems beyond your understanding) or you just don't have a
valid criteria to use.
>
>
>> Therefore, you may reformulate the
>> requirement:
>>
>> ∀x ∈ Turing_Machines_Descriptions
>> ∀y ∈ Finite_Strings
>> H(x,y) returns "yes" if UTM(x,y) halts and "no" otherwise.
>>
>
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