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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory,sci.logic
Subject: Re: Two dozen people were simply wrong --- Try to prove otherwise ---
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Date: Sat, 1 Jun 2024 18:19:39 +0200
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Op 01.jun.2024 om 18:13 schreef olcott:
> On 6/1/2024 10:56 AM, Richard Damon wrote:
>> On 6/1/24 11:30 AM, olcott wrote:
>>>
>>> *I will not discuss any other points with you until after you either*
>>> (a) Acknowledge that DD correctly simulated by HH and ⟨Ĥ⟩ ⟨Ĥ⟩ correctly
>>>      simulated by embedded_H remain stuck in recursive simulation for
>>>      1 to ∞ of correct simulation or
>>>
>>> (b) Correctly prove otherwise.
>>
>> And until you answer the question of what that actually means, I will 
>> reply WHO CARES.
>>
> 
> typedef int (*ptr)();  // ptr is pointer to int function in C
> 00       int HH(ptr p, ptr i);
> 01       int DD(ptr p)
> 02       {
> 03         int Halt_Status = HH(p, p);
> 04         if (Halt_Status)
> 05           HERE: goto HERE;
> 06         return Halt_Status;
> 07       }
> 08
> 09       int main()
> 10       {
> 11         HH(DD,DD);
> 12         return 0;
> 13       }
> 
> Every DD correctly simulated by any HH of the infinite set of HH/DD
> pairs that match the above template never reaches past its own simulated
> line 03 in 1 to ∞ steps of correct simulation of DD by HH.
> 
> In this case HH is either a pure simulator that never halts or
> HH is a pure function that stops simulating after some finite number
> of simulated lines. The line count is stored in a local variable.
> The pure function HH always returns the meaningless value of 56
> after it stops simulating.
> 

The simulated D never reaches past line 03, because the simulated HH 
never halts in 1 to ∞ steps of correct simulation of HH by HH.
I have told you that so many times.
HH is required to halt, thus HH does not match the requirement.