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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory,sci.logic
Subject: Re: Two dozen people were simply wrong --- Try to prove otherwise ---
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Date: Sat, 1 Jun 2024 20:54:53 +0200
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Op 01.jun.2024 om 20:07 schreef olcott:
> On 6/1/2024 12:56 PM, Richard Damon wrote:
>> On 6/1/24 1:44 PM, olcott wrote:
>>> On 6/1/2024 12:33 PM, Richard Damon wrote:
>>>> On 6/1/24 1:27 PM, olcott wrote:
>>>>> On 6/1/2024 12:22 PM, Richard Damon wrote:
>>>>>> On 6/1/24 12:38 PM, olcott wrote:
>>>>>>> On 6/1/2024 11:27 AM, Richard Damon wrote:
>>>>>>>> On 6/1/24 12:13 PM, olcott wrote:
>>>>>>>>> On 6/1/2024 10:56 AM, Richard Damon wrote:
>>>>>>>>>> On 6/1/24 11:30 AM, olcott wrote:
>>>>>>>>>>>
>>>>>>>>>>> *I will not discuss any other points with you until after you 
>>>>>>>>>>> either*
>>>>>>>>>>> (a) Acknowledge that DD correctly simulated by HH and ⟨Ĥ⟩ ⟨Ĥ⟩ 
>>>>>>>>>>> correctly
>>>>>>>>>>>      simulated by embedded_H remain stuck in recursive 
>>>>>>>>>>> simulation for
>>>>>>>>>>>      1 to ∞ of correct simulation or
>>>>>>>>>>>
>>>>>>>>>>> (b) Correctly prove otherwise.
>>>>>>>>>>
>>>>>>>>>> And until you answer the question of what that actually means, 
>>>>>>>>>> I will reply WHO CARES.
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> typedef int (*ptr)();  // ptr is pointer to int function in C
>>>>>>>>> 00       int HH(ptr p, ptr i);
>>>>>>>>> 01       int DD(ptr p)
>>>>>>>>> 02       {
>>>>>>>>> 03         int Halt_Status = HH(p, p);
>>>>>>>>> 04         if (Halt_Status)
>>>>>>>>> 05           HERE: goto HERE;
>>>>>>>>> 06         return Halt_Status;
>>>>>>>>> 07       }
>>>>>>>>> 08
>>>>>>>>> 09       int main()
>>>>>>>>> 10       {
>>>>>>>>> 11         HH(DD,DD);
>>>>>>>>> 12         return 0;
>>>>>>>>> 13       }
>>>>>>>>>
>>>>>>>>> Every DD correctly simulated by any HH of the infinite set of 
>>>>>>>>> HH/DD
>>>>>>>>> pairs that match the above template never reaches past its own 
>>>>>>>>> simulated
>>>>>>>>> line 03 in 1 to ∞ steps of correct simulation of DD by HH.
>>>>>>>>>
>>>>>>>>> In this case HH is either a pure simulator that never halts or
>>>>>>>>> HH is a pure function that stops simulating after some finite 
>>>>>>>>> number
>>>>>>>>> of simulated lines. The line count is stored in a local variable.
>>>>>>>>> The pure function HH always returns the meaningless value of 56
>>>>>>>>> after it stops simulating.
>>>>>>>>>
>>>>>>>>
>>>>>>>> So, still no answer, to teh question. 
>>>>>>>
>>>>>>> You can pretend that you don't understand something that you do 
>>>>>>> indeed
>>>>>>> understand into perpetuity.
>>>>>>>
>>>>>>> The key measure of dishonestly would be that you continue to say
>>>>>>> that you don't understand yet never ever point out exactly what you
>>>>>>> don't understand and why you don't understand it.
>>>>>>>
>>>>>>>> I giuess that Mean YOU don't even know what you are asking, 
>>>>>>>> though it seems that now you are admitting that your HH doesn't 
>>>>>>>> actually ANSWER the question, so it isn't ACTUALL a decider for 
>>>>>>>> any function except the "56" mapping.
>>>>>>>>
>>>>>>>> I will repeat the question and until you answer the question of 
>>>>>>>> what that actually means, I will reply WHO CARES.
>>>>>>>>
>>>>>>>> DO you mean the simulation of the TEMPLATE DD, 
>>>>>>>
>>>>>>> *Of course I don't mean that nonsense. I mean exactly what I 
>>>>>>> specified*
>>>>>>>
>>>>>>>> which means that we CAN'T simulate the call HH as we have no 
>>>>>>>> code past point to simulate, and thus your claim is just a LIE.
>>>>>>>>
>>>>>>>> Or, do you mean a given instance of HH simulating a given 
>>>>>>>> instance of DD, at which point we never have the 1 to infinte 
>>>>>>>> number of simulatons of THAT INPUT, so your claim is just a LIE.
>>>>>>>>
>>>>>>>
>>>>>>> Every element of the infinite set of every H/D pairs...
>>>>>>> Every element of the infinite set of every H/D pairs...
>>>>>>> Every element of the infinite set of every H/D pairs...
>>>>>>>
>>>>>>> *Its not that hard when one refrains from dishonesty*
>>>>>>> We can't even say that you forgot these details from one reply
>>>>>>> to the next because the details are still in this same post.
>>>>>>>
>>>>>>
>>>>>> And every one gives a meaningless answer, 
>>>>>
>>>>> *THEN TRY TO REFUTE THIS UNEQUIVOCAL STATEMENT*
>>>>> DD correctly emulated by HH with an x86 emulator cannot possibly
>>>>> reach past its own machine instruction [00001c2e] in any finite
>>>>> number of steps of correct emulation.
>>>>>
>>>>
>>>> Why? I don't care about it.
>>>>
>>>> As I have said, the implication of your definition of "Correct 
>>>> SImulation" means that this says NOTHING about the halting behavior 
>>>> of DD. (only not halted yet)
>>>>
>>>
>>> *THEN TRY TO REFUTE THIS UNEQUIVOCAL STATEMENT*
>>> DD correctly emulated by HH with an x86 emulator cannot possibly
>>> reach past its own machine instruction [00001c2e] in any finite
>>> *or infinite* number of steps of correct emulation.
>>>
>>> When I say it that way you claim to be confused and what I do
>>> not say it that way you claim what I say is incomplete proof.
>>
>> WHy do I care? I won't spend the effort to even try to refute 
>> something that is clearly meaningless.
>>
>> You seem to have a conflict of definitions, as a given DD will only 
>> ever be simulated by ONE given HH that only simuates for one number of 
>> steps.
>>
> 
> typedef int (*ptr)();  // ptr is pointer to int function in C
> 00       int HH(ptr p, ptr i);
> 01       int DD(ptr p)
> 02       {
> 03         int Halt_Status = HH(p, p);
> 04         if (Halt_Status)
> 05           HERE: goto HERE;
> 06         return Halt_Status;
> 07       }
> 08
> 09       int main()
> 10       {
> 11         HH(DD,DD);
> 12         return 0;
> 13       }
> 
> You continue to either fail to understand or seemingly more likely
> simply lie about the fact that every DD correctly simulated by any
> HH that can possibly exist cannot possibly reach past its own line 03.

Only if the simulation of HH simulated by HH does not reach HH's return, 
otherwise the simulation of DD would go to line 04.

> 
> *THIS MEANS THAT THE INPUT TO HH(DD,DD) DOES NOT HALT*
> *THIS MEANS THAT THE INPUT TO HH(DD,DD) DOES NOT HALT*
> *THIS MEANS THAT THE INPUT TO HH(DD,DD) DOES NOT HALT*
> 

If true: The input to HH is both DD and HH called by DD, so both DD and 
HH do not halt, but keep starting new instances of each other.
However, HH is required to halt, but it doesn't. So, the HH that halts 
is phantasy.