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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory,sci.logic
Subject: Re: Two dozen people were simply wrong --- Try to prove otherwise ---
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Date: Sat, 1 Jun 2024 21:04:53 +0200
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Op 01.jun.2024 om 20:44 schreef olcott:
> On 6/1/2024 1:40 PM, Fred. Zwarts wrote:
>> Op 01.jun.2024 om 18:24 schreef olcott:
>>> On 6/1/2024 11:19 AM, Fred. Zwarts wrote:
>>>> Op 01.jun.2024 om 18:13 schreef olcott:
>>>>> On 6/1/2024 10:56 AM, Richard Damon wrote:
>>>>>> On 6/1/24 11:30 AM, olcott wrote:
>>>>>>>
>>>>>>> *I will not discuss any other points with you until after you 
>>>>>>> either*
>>>>>>> (a) Acknowledge that DD correctly simulated by HH and ⟨Ĥ⟩ ⟨Ĥ⟩ 
>>>>>>> correctly
>>>>>>>      simulated by embedded_H remain stuck in recursive simulation 
>>>>>>> for
>>>>>>>      1 to ∞ of correct simulation or
>>>>>>>
>>>>>>> (b) Correctly prove otherwise.
>>>>>>
>>>>>> And until you answer the question of what that actually means, I 
>>>>>> will reply WHO CARES.
>>>>>>
>>>>>
>>>>> typedef int (*ptr)();  // ptr is pointer to int function in C
>>>>> 00       int HH(ptr p, ptr i);
>>>>> 01       int DD(ptr p)
>>>>> 02       {
>>>>> 03         int Halt_Status = HH(p, p);
>>>>> 04         if (Halt_Status)
>>>>> 05           HERE: goto HERE;
>>>>> 06         return Halt_Status;
>>>>> 07       }
>>>>> 08
>>>>> 09       int main()
>>>>> 10       {
>>>>> 11         HH(DD,DD);
>>>>> 12         return 0;
>>>>> 13       }
>>>>>
>>>>> Every DD correctly simulated by any HH of the infinite set of HH/DD
>>>>> pairs that match the above template never reaches past its own 
>>>>> simulated
>>>>> line 03 in 1 to ∞ steps of correct simulation of DD by HH.
>>>>>
>>>>> In this case HH is either a pure simulator that never halts or
>>>>> HH is a pure function that stops simulating after some finite number
>>>>> of simulated lines. The line count is stored in a local variable.
>>>>> The pure function HH always returns the meaningless value of 56
>>>>> after it stops simulating.
>>>>>
>>>>
>>>> The simulated D never reaches past line 03, because the simulated HH 
>>>> never halts in 1 to ∞ steps of correct simulation of HH by HH.
>>>> I have told you that so many times.
>>>> HH is required to halt, thus HH does not match the requirement.
>>>
>>>
>>> HH correctly reports that because DD calls HH(DD,DD) in
>>> recursive simulation that DD never halts.
>>>
>>> HHH(HH,DD,DD) would report that HH halts.
>>>
>>
>> Maybe. And H1 (DD,DD) would report that DD halts.
>>
>> In the recursive simulation by HH, neither the simulation of DD, nor 
>> the simulation of HH halts. If one of them would halt, the other one 
>> would halt as well.
>>
>> So HH 'correctly' reports that both DD and HH do not halt, because 
>> they both keep starting an instance of each other.
> 
> 
> I will not respond to any of your replies while you continue to play
> head games.
> 
> *Changing the subject away from this is construed as a head game*

Bad excuse. I am not changing the subject. I show that the requirements 
of HH in the subject are contradictory.

> DD correctly simulated by pure function HH cannot possibly reach
> past its own line 03 in any finite number of steps of correct
> simulation.

Only, because the simulation of HH did not halt.

> 
> In case you didn't know pure functions must halt because they must
> return a value.
> 

I know that HH is required to halt, but your own words implies that it 
doesn't. So apparently your HH does not match its requirements.

Correct me if I am wrong and show the trace of the simulated HH that 
reaches its final state and the next 10 instructions.