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From: joes <noreply@example.com>
Newsgroups: comp.theory
Subject: Re: Two dozen people were simply wrong --- Try to prove otherwise ---
 pinned down
Date: Sun, 2 Jun 2024 09:18:35 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Sat, 01 Jun 2024 13:44:21 -0500 schrieb olcott:

> On 6/1/2024 1:40 PM, Fred. Zwarts wrote:
>> Op 01.jun.2024 om 18:24 schreef olcott:
>>> On 6/1/2024 11:19 AM, Fred. Zwarts wrote:
>>>> Op 01.jun.2024 om 18:13 schreef olcott:
>>>>> On 6/1/2024 10:56 AM, Richard Damon wrote:
>>>>>> On 6/1/24 11:30 AM, olcott wrote:
>>>>>>>
>>>
>>> HH correctly reports that because DD calls HH(DD,DD) in recursive
>>> simulation that DD never halts.
>>>
>>> HHH(HH,DD,DD) would report that HH halts.
>>>
>>>
>> Maybe. And H1 (DD,DD) would report that DD halts.
>> 
>> In the recursive simulation by HH, neither the simulation of DD, nor
>> the simulation of HH halts. If one of them would halt, the other one
>> would halt as well.
>> 
>> So HH 'correctly' reports that both DD and HH do not halt, because they
>> both keep starting an instance of each other.


> In case you didn't know pure functions must halt because they must
> return a value.
That means it terminates/returns, right? Then H is either not „pure”,
or execution proceeds past line 4.

-- 
joes