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From: joes <noreply@example.com>
Newsgroups: comp.theory
Subject: Re: D correctly simulated by H cannot possibly reach its own line 06
 and halt
Date: Sun, 2 Jun 2024 09:51:53 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Sat, 01 Jun 2024 13:37:19 -0500 schrieb olcott:
> On 6/1/2024 1:33 PM, joes wrote:
>> Am Fri, 31 May 2024 10:54:24 -0500 schrieb olcott:
>>> On 5/31/2024 10:37 AM, Fred. Zwarts wrote:
>>>> Op 31.mei.2024 om 16:25 schreef olcott:
>>>>> On 5/31/2024 2:50 AM, Fred. Zwarts wrote:
>>>>>> Op 31.mei.2024 om 00:01 schreef olcott:
>>>>>>> On 5/30/2024 4:54 PM, joes wrote:
>>>>>>>> Am Thu, 30 May 2024 09:55:24 -0500 schrieb olcott:
>>>>>>>>
>>>>> *pure function H definitely halts you are confused*
>>>>>
>>>> You can assume a unicorn, but that does not make it existent. You can
>>>> assume a simulating H that is a pure function and halts, but that
>>>> does not make them existent. The set of such H is empty.
>>>
>>> You simply ignored my proof that you are wrong.
>> How about you show a terminating H that behaves the same as an infinite
>> loop?
Waiting in an infinite loop…

>>> D correctly simulated by pure function HH cannot possibly reach its
>>> own final state at line 06 in any finite number of steps of correct
>>> simulation.
>>> You keep ignoring that when HH simulates a finite number of steps of
>>> DD that *this means that HH reaches its final state and halts*

>> If D doesn't halt, H must likewise simulate an infinite number of steps
>> or be incorrect.
> I will not respond to any of your replies while you continue to play
> head games.
After how many steps does H halt?

However many steps D takes, if it halts.

> *Changing the subject away from this is construed as a head game* DD
> correctly simulated by pure function HH cannot possibly reach past its
> own line 03 in any finite number of steps of correct simulation.

-- 
joes