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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory
Subject: =?UTF-8?Q?Re=3A_A_simulating_halt_decider_applied_to_the_The_Peter_?=
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Date: Sun, 2 Jun 2024 13:23:15 -0400
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On 6/2/24 9:07 AM, olcott wrote:
> On 6/2/2024 2:36 AM, Mikko wrote:
>> On 2024-06-01 14:37:01 +0000, olcott said:
>>
>>> On 6/1/2024 2:52 AM, Mikko wrote:
>>>> On 2024-05-31 15:35:18 +0000, olcott said:
>>>
>>>>>
>>>>> When Ĥ is applied to ⟨Ĥ⟩
>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy ∞
>>>>> Ĥ.q0 ⟨Ĥ⟩ ⊢* embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
>>>>
>>>> Of those two lines one is false.
>>>> As embedded_H is a copy of H both lines imply that H is not a halt 
>>>> decider.
>>>>
>>>>> *Formalizing the Linz Proof structure*
>>>>> ∃H  ∈ Turing_Machines
>>>>> ∀x  ∈ Turing_Machine_Descriptions
>>>>> ∀y  ∈ Finite_Strings
>>>>> such that H(x,y) = Halts(x,y)
>>>>
>>>> As already noted, the above is not a part of a proof structure.
>>>>
>>>
>>> Unless and until you provide reasoning to back that up it counts
>>> as if you said nothing about it.
>>
>> If there are no more questions about the details of the reasoning
>> we may assume that the presiented reasoning is sufficieant.
>>
> 
> The above <is> the structure of his proof your empty assertion utterly 
> bereft of any supporting (EAUBoaSR)) reasoning counts for zilch.
> 
> Linz claims that of every Turing Machine there are none that solve the 
> halting problem.
> 
> ∃!H  ∈ Turing_Machines  (What Richard was saying)
> would say that there does not exist exactly one Turing Machine that
> solves the halting problem thus fails if there are more than one.
> 

I never said that, which prove you to be a LILAR.

That yo might think I said that just shows that you are an IDIOT.