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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory,sci.logic
Subject: Re: Two dozen people were simply wrong --- Try to prove otherwise ---
 pinned down --- canonical
Date: Sun, 2 Jun 2024 20:55:34 +0200
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Op 02.jun.2024 om 20:39 schreef olcott:
> On 6/2/2024 1:24 PM, Fred. Zwarts wrote:
>> Op 02.jun.2024 om 16:47 schreef olcott:
>>> On 6/2/2024 4:24 AM, Fred. Zwarts wrote:
>>>> Op 01.jun.2024 om 23:27 schreef olcott:
>>>>> On 6/1/2024 4:15 PM, Richard Damon wrote:
>>>>>> On 6/1/24 4:35 PM, olcott wrote:
>>>>>>> On 6/1/2024 3:29 PM, Richard Damon wrote:
>>>>>>>> On 6/1/24 12:46 PM, olcott wrote:
>>>>>>>>> On 6/1/2024 11:33 AM, Richard Damon wrote:
>>>>>>>>>> On 6/1/24 12:18 PM, olcott wrote:
>>>>>>>>>>> On 6/1/2024 11:08 AM, Richard Damon wrote:
>>>>>>>>>>>> On 6/1/24 11:58 AM, olcott wrote:
>>>>>>>>>>>>> On 6/1/2024 10:46 AM, Richard Damon wrote:
>>>>>>>>>>>>>> On 6/1/24 10:00 AM, olcott wrote: >> DD correctly 
>>>>>>>>>>>>>> simulated by HH remains stuck in recursive simulation
>>>>>>>>>>>>>>> all the time it is simulated even when an infinite number 
>>>>>>>>>>>>>>> of steps
>>>>>>>>>>>>>>> are simulated.
>>>>>>>>>>>>>>
>>>>>>>>>>>>>> So, are you admitting that HH just gets stuck and doesn't 
>>>>>>>>>>>>>> answer when asked HH(DD,DD)?
>>>>>>>>>>>>>>
>>>>>>>>>>>>>
>>>>>>>>>>>>> Every DD correctly simulated by any HH remains stuck in 
>>>>>>>>>>>>> recursive simulation for 1 to ∞ steps of correct simulation.
>>>>>>>>>>>>
>>>>>>>>>>>> So? Since you definition of "Correct Simulation" is 
>>>>>>>>>>>> non-canonical, that doesn't mean anything.
>>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> *When the "canonical" definition tries to get away with 
>>>>>>>>>>> refuting this*
>>>>>>>>>>>
>>>>>>>>>>> DD correctly emulated by HH with an x86 emulator cannot possibly
>>>>>>>>>>> reach past its own machine instruction [00001c2e] in any finite
>>>>>>>>>>> number of steps of correct emulation.
>>>>>>>>>>
>>>>>>>>>> No, it doesn't "Refute" that, 
>>>>>>>>>
>>>>>>>>> *Then what I said stands unrefuted*
>>>>>>>>> *Then what I said stands unrefuted*
>>>>>>>>> *Then what I said stands unrefuted*
>>>>>>>>
>>>>>>>> And unproven, and still meaningless.
>>>>>>>>
>>>>>>>>>
>>>>>>>>> *We can't move on to any other point until*
>>>>>>>>> (a) You acknowledge that my above statement about the behavior 
>>>>>>>>> of the
>>>>>>>>> x86 machine code of DD is irrefutable and applies to the C 
>>>>>>>>> source code version of DD and applies to the Linz proof.
>>>>>>>>>
>>>>>>>>> (b) You correctly refute what I said above about the behavior 
>>>>>>>>> of the
>>>>>>>>> x86 machine code of DD.
>>>>>>>>
>>>>>>>> But why do we care about the fact that all your HH that answer 
>>>>>>>> just gave up on their simulation before the actual canonically 
>>>>>>>> correct simulation would have reached a final state, 
>>>>>>> It seems to me (and I may be wrong you may be confused)
>>>>>>> That we cannot move on to any other point simply because
>>>>>>> you are simply too freaking dishonest.
>>>>>>>
>>>>>>> You use moving on to other points to endlessly avoid any
>>>>>>> closure on any point.
>>>>>>>
>>>>>>
>>>>>>
>>>>>> We can not move on, because you want to base your arguement on 
>>>>>> falsehoods.
>>>>>>
>>>>>
>>>>> typedef int (*ptr)();  // ptr is pointer to int function in C
>>>>> 00       int HH(ptr p, ptr i);
>>>>> 01       int DD(ptr p)
>>>>> 02       {
>>>>> 03         int Halt_Status = HH(p, p);
>>>>> 04         if (Halt_Status)
>>>>> 05           HERE: goto HERE;
>>>>> 06         return Halt_Status;
>>>>> 07       }
>>>>> 08
>>>>> 09       int main()
>>>>> 10       {
>>>>> 11         HH(DD,DD);
>>>>> 12         return 0;
>>>>> 13       }
>>>>>
>>>>> Every DD correctly simulated by any HH of the infinite set of HH/DD
>>>>> pairs that match the above template never reaches past its own 
>>>>> simulated
>>>>> line 03 in 1 to ∞ steps of correct simulation of DD by HH.
>>>>
>>>> Similarly:
>>>> Every HH correctly simulated by itself of the infinite set of HH/DD
>>>> pairs that match the above template never reaches past its own 
>>>> simulated
>>>> return in 1 to ∞ steps of correct simulation of HH by HH.
>>>>
>>>
>>> DD correctly simulated by HH includes HH correctly simulating itself
>>> simulating DD as an intrinsic aspect of DD correctly simulated by HH. 
>>> > *It is only the outermost directly executed HH that is required to 
>>> halt*
>>
>> It might be possible to use the following criteria to see whether a 
>> program halts:
>> a) The direct executed program halts.
>> b) The simulation of the program by HH reaches its final state.
>>
>> If you choose a then both DD and HH halt.
>> If you choose b then neither DD, nor HH halt.
>>
>> Choosing different criteria for different functions only because you 
>> need it in your claim would be dishonest.
>>
>>>
>>> When an input DD gets instances of itself HH stuck in recursive
>>> simulation this input is rejected as non-halting.
>>
>> Similarly, when the partial input HH (part of DD) gets instances of 
>> itself HH stuck in recursive simulation this partial input is rejected 
>> as non-halting.
>>
>>
> 
> *I always use this same criteria* 
So, what is it? a or b?