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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic
Subject: Re: Why does Olcott care about simulation, anyway? --- Mikes Review
Date: Mon, 3 Jun 2024 20:46:42 -0500
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On 6/3/2024 8:38 PM, Mike Terry wrote:
> On 03/06/2024 18:54, olcott wrote:
>> On 6/3/2024 11:25 AM, Mike Terry wrote:
>>> On 03/06/2024 04:50, olcott wrote:
>>>> On 6/2/2024 10:28 PM, Mike Terry wrote:
>>>>> On 03/06/2024 01:16, immibis wrote:
>>>>>> The halting problem says you can't find a Turing machine that
>>>>>> tells whether executing each other Turing machine will halt.
>>>>>> Simulation has nothing to do with the question.
>>>>>
>>>>> Background:
>>>>>
>>>>> PO claims to have refuted the common HP proof, e.g. as covered in
>>>>> the Linz book "An Introduction to Formal Languages and Automata".
>>>>> PO occasionally posts a link to a PDF containing an extract of the
>>>>> 5 or so pages of the book containing the proof, but I expect you
>>>>> have access to this or equivalent.
>>>>>
>>>>> In a nutshell, the proof goes:
>>>>> - Suppose H is a TM Halt decider that decides for any input <P><I>
>>>>> whether
>>>>> TM P run with input I on its input tape halts.
>>>>> [<P> is the string representation of the actual TM P, and
>>>>> <I> is the string representation of input tape I]
>>>>> - Construct from H a new TM H^ using the mechanical process
>>>>> described in the proof.
>>>>> If H exists, then its corresponding H^ also exists.
>>>>> - Show that the construction of H^ ensures that:
>>>>> - if H decides input <H^><H^> (representing H^ running with
>>>>> input <H^>) halts,
>>>>> then that implies that H^ running with input <H^> never halts
>>>>> - if H decides input <H^><H^> never halts,
>>>>> then that implies H^ running with input <H^> halts
>>>>> I.e. either way, H decides the specific input <H^><H^>
>>>>> incorrectly, contradicting
>>>>> the initial assumption that H is a halt decider.
>>>>> - So no halt decider exists. (Every proposed halt decider decides
>>>>> at least one input case
>>>>> incorrectly, viz input <H^><H^>.)
>>>>>
>>>>> PO basically claimed he had a fully coded TM H, which CORRECTLY
>>>>> decides its "nemesis" input <H^><H^>, contradicting the logic of
>>>>> the Linz proof [without pointing out any actual mistake in the Linz
>>>>> proof]. Given most people here understand the Linz proof well
>>>>> enough to see it is basically sound, people were sceptical!
>>>>>
>>>>> It turned out PO was lying about the fully coded TM, and in fact
>>>>> what he actually had was the idea behind a C program which would
>>>>> "prove" his idea. A couple of years(?) later he actually completed
>>>>> his C program and his x86utm.exe which would simulate the x86 code
>>>>> of his H and H^ to "prove" his claim. His equivalent of Linz H is
>>>>> his C function H or HH, and his equivalent of Linz H^ is his D or
>>>>> DD respectively. (They run under x86utm.exe and are not
>>>>> Windows/Unix executables.)
>>>>>
>>>>> H/HH use PARTIAL simulation of their input to decide
>>>>> halting/non-halting, returning
>>>>> 0 or 1 to communicate their decision. As you correctly point out,
>>>>> to the HP proof simulation is quite irrelevant, being just one kind
>>>>> of data manipulation that H may perform on its input string <P><I>
>>>>> before it decides the halting status. So the Linz HP proof covers
>>>>> such H, no problem.
>>>>> [I put PARTIAL in caps, just because there seems to be some
>>>>> confusion in recent threads as to what PO means by "simulation".
>>>>> He doesn't say it explicitly, despite suggestions to this effect,
>>>>> but he always means what might be called /partial/ simulation.]
>>>>>
>>>>> PO believes that by (partially) simulating the computation
>>>>> corresponding to the input <P><I> [i.e. calculating the successive
>>>>> x86 instruction steps of the computation P(I)] and monitoring the
>>>>> progress of virtual x86 state changes (like instruction address and
>>>>> op-code and so on) H could spot some pattern that reveals whether
>>>>> computation P(I) halts or not. At this point in the partial
>>>>> simulation, his H would stop simulating (aka "abort" the
>>>>> simulation) and return the appropriate halt status for input <P><I>.
>>>>>
>>>>> Nothing remarkable so far! Clearly a tight-loop in P /can/ be
>>>>> detected in this fashion, so /some/ <P><I> inputs /can/ be
>>>>> correctly determined like this. The PO claim however is that the
>>>>> specific input <H^><H^> is correctly decided by his H. In C terms
>>>>> those correspond to H(D,D) correctly returning the halt status of
>>>>> computation D(D). [PO would probably dispute this, because he
>>>>> doesn't properly understand halting or the HP generally, or in fact
>>>>> pretty much /any abstract concept/ ]
>>>>>
>>>>
>>>> Introduction to the Theory of Computation, by Michael Sipser
>>>> https://www.amazon.com/Introduction-Theory-Computation-Michael-Sipser/dp/113318779X/
>>>>
>>>> On 10/13/2022 11:29:23 AM
>>>> MIT Professor Michael Sipser agreed this verbatim paragraph is correct
>>>> (He has neither reviewed nor agreed to anything else in this paper)
>>>>
>>>> <Professor Sipser agreed>
>>>> If simulating halt decider H correctly simulates its input D until H
>>>> correctly determines that its simulated D would never stop running
>>>> unless aborted then
>>>>
>>>> H can abort its simulation of D and correctly report that D specifies a
>>>> non-halting sequence of configurations.
>>>> </Professor Sipser agreed>
>>>>
>>>> I have started working on what seem to be some computability issues
>>>> that you pointed out with my HH. I found that they are isolated to
>>>> one single element of HH. Essentially the details of how the master
>>>> UTM directly executed HH passes a portion of its tape to its slaves.
>>>>
>>>> Nothing else seems to have any computability issues by the measure
>>>> that I am using.
>>>>
>>>> Message-ID: <rLmcnQQ3-N_tvH_4nZ2dnZfqnPGdnZ2d@brightview.co.uk>
>>>> On 3/1/2024 12:41 PM, Mike Terry wrote:
>>>> >
>>>> > Obviously a simulator has access to the internal state
>>>> > (tape contents etc.) of the simulated machine. No problem there.
>>>>
>>>> Because of your above comment it seems that correcting this
>>>> tiny computability issue with HH is my best path forward.
>>>>
>>>>
>>>>
>>>>
>>>> You have given the following a blatantly false review when I
>>>> said the same thing another way:
>>>
>>> I have no idea what you're talking about. I did not write any of
>>> what follows below.
>>>
>>> Also I don't believe I said anything "blatantly false". You're
>>> incapable of judging what other people say or are thinking - you're
>>> often telling people that they'er lying to you and denying
>>> "previously verified facts" etc. but its all rubbish - you're in no
>>> position to make such judgements.
>>>
>>>
>>> Mike.
>>>
>>
>> You said that the execution trace that I proved is correct is
>> incorrect because you didn't like the way that HH was written.
>> You said this without looking at my proof as you are doing
>> here again.
>
> An execution trace that is produced by a program that is incorrect
> /proves/ nothing whatsoever. I don't need to look at your proof, as I
> was commenting on the value of your program output AS PROOF.
>
I provided the execution trace that HH derives
*AND THE X86 SOURCE-CODE OF DD THAT PROVES THIS TRACE IS CORRECT*
*AND THE X86 SOURCE-CODE OF DD THAT PROVES THIS TRACE IS CORRECT*
*AND THE X86 SOURCE-CODE OF DD THAT PROVES THIS TRACE IS CORRECT*
http://al.howardknight.net/?STYPE=msgid&MSGI=%3CS8CcnRadHexfe8X7nZ2dnZfqnPqdnZ2d%40brightview.co.uk%3E+
Message-ID: <S8CcnRadHexfe8X7nZ2dnZfqnPqdnZ2d@brightview.co.uk>
AND YOU SAID
"It shows that the simulation is "rubbish" and any trace
produced by it can just be ignored."
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer