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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory
Subject: Re: How Partial Simulations correctly determine non-halting ---Ben's
 10/2022 analysis
Date: Sun, 9 Jun 2024 14:08:53 -0400
Organization: i2pn2 (i2pn.org)
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On 6/9/24 12:09 PM, olcott wrote:
> On 6/9/2024 10:11 AM, Mikko wrote:
>> On 2024-06-09 13:59:57 +0000, olcott said:
>>
>>> On 6/9/2024 3:47 AM, Mikko wrote:
>>>> On 2024-06-08 13:04:14 +0000, olcott said:
>>>>
>>>>> On 6/8/2024 1:42 AM, Mikko wrote:
>>>>>> On 2024-06-07 22:26:05 +0000, olcott said:
>>>>>>
>>>>>>> On 6/7/2024 4:00 PM, joes wrote:
>>>>>>>> Am Fri, 07 Jun 2024 09:47:35 -0500 schrieb olcott:
>>>>>>>>> On 6/7/2024 1:30 AM, Mikko wrote:
>>>>>>>>>> On 2024-06-06 15:31:36 +0000, olcott said:
>>>>>>>>>>> On 6/6/2024 10:14 AM, Mikko wrote:
>>>>>>>>>>>> On 2024-06-06 13:53:58 +0000, olcott said:
>>>>>>>>>>>>> On 6/6/2024 5:15 AM, Mikko wrote:
>>>>>>>>>>>>>> On 2024-06-05 13:29:28 +0000, olcott said:
>>>>>>>>>>>>>>> On 6/5/2024 2:37 AM, Mikko wrote:
>>>>>>>>>>>>>>>> On 2024-06-04 18:02:03 +0000, olcott said:
>>>>>>>>
>>>>>>>>> A simulating halt decider cannot report on what the behavior of a
>>>>>>>>> non-terminating input actually is because this would take forever.
>>>>>>>> Exactly. Didn't you say it is allowed to abort?
>>>>>>>>
>>>>>>>>> H is not allowed to report on any computation containing its 
>>>>>>>>> actual self
>>>>>>>>> because Turing machines can only take finite string inputs thus 
>>>>>>>>> cannot
>>>>>>>>> take Turing machines as inputs.
>>>>>>>> Bullshit. It can take other machines just fine. It doesn't know 
>>>>>>>> about
>>>>>>>> itself.
>>>>>>>>
>>>>>>>
>>>>>>> No actual Turing machine can be the input to any other actual
>>>>>>> Turing machine. Turing machines only take finite string inputs.
>>>>>>
>>>>>> Any finite string can be an input to some Turing machine.
>>>>>> Can you prove that a Turing machine is not a finite string?
>>>>>>
>>>>>
>>>>> By definition Turing Machines are not finite strings in the
>>>>> conventional model. In my x86utm model of computation x86
>>>>> machine language <is> the input to another function written
>>>>> in the x86 language.
>>>>
>>>> The definition does not say "Turing machine is not a finite string".
>>>
>>> The definition of puppy does not say it is not a fifteen
>>> story office building.
>>
>> Therefore you must use a different kind of argumentation if you want
>> to claim that a Turing machine is not a finite string.
>>
> 
> It is common knowledge (that you lack) that a Turing machine
> <is not> a finite string. It is also common knowledge that
> finite strings can describe Turing machines.
> 

It is also common knowledge that "strings" don't have behavior

So, since we need to look at what the string describess for the 
behavior, the fact that that string could be a description of a Turing 
Machine, that becomes a perfectly valid "behavior" for the string when 
you are being a bit sloppy in your language.

You can't argue that HH can not be responsible for the behavior of the 
Turing machine described by the input, and claim it is (at least tryihg 
to be) a Halt Decider, since that definition provides the meaning for 
the input.