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From: joes <noreply@example.com>
Newsgroups: comp.theory
Subject: Re: Simplified proof that DDD correctly simulated by HHH does not
 halt
Date: Sun, 9 Jun 2024 19:13:26 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Sun, 09 Jun 2024 13:23:04 -0500 schrieb olcott:
> On 6/9/2024 12:59 PM, joes wrote:
>> Am Sun, 09 Jun 2024 11:07:19 -0500 schrieb olcott:
>>> typedef void (*ptr)(); // pointer to void function 01   void HHH(ptr
>>> P, ptr I)
>>> 02   {
>>> 03     P(I);
>>> 04     return;
>>> 05   }
>>> 06 07   void DDD(int (*x)())
>>> 08   {
>>> 09     HHH(x, x);
>>> 10     return;
>>> 11   }
>>> 12 13   int main()
>>> 14   {
>>> 15     HHH(DDD,DDD);
>>> 16   }
>>> 17
>> 
>>> In the above Neither DDD nor HHH ever reach their own return statement
>>> thus never halt.
>>> Most of my reviewers incorrectly believe that when HH(DD,DD) aborts
>>> its simulated input that this simulated input halts.
> 
> You chopped out the mandatory prerequisite.
> Please go back and prove that you understand what infinite recursion is
> before proceeding.
Dude, I've got nothing to prove to you. You instead could explain how you
can call a simulation that differs from the direct execution "correct".
Or why H and HH are different.

-- 
joes