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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic
Subject: Re: D correctly simulated by H proved for THREE YEARS ---
Date: Sun, 9 Jun 2024 22:54:52 -0500
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*No one has verified the actual facts of this for THREE YEARS*
*No one has verified the actual facts of this for THREE YEARS*
*No one has verified the actual facts of this for THREE YEARS*

On 5/29/2021 2:26 PM, olcott wrote:
https://groups.google.com/g/comp.theory/c/dTvIY5NX6b4/m/cHR2ZPgPBAAJ

THE ONLY POSSIBLE WAY for D simulated by H to have the same
behavior as the directly executed D(D) is for the instructions
of D to be incorrectly simulated by H (details provided below).

_D()
[00000cfc](01)  55                      push ebp
[00000cfd](02)  8bec                    mov ebp,esp
[00000cff](03)  8b4508                  mov eax,[ebp+08]
[00000d02](01)  50                      push eax       ; push D
[00000d03](03)  8b4d08                  mov ecx,[ebp+08]
[00000d06](01)  51                      push ecx       ; push D
[00000d07](05)  e800feffff              call 00000b0c  ; call H
[00000d0c](03)  83c408                  add esp,+08
[00000d0f](02)  85c0                    test eax,eax
[00000d11](02)  7404                    jz 00000d17
[00000d13](02)  33c0                    xor eax,eax
[00000d15](02)  eb05                    jmp 00000d1c
[00000d17](05)  b801000000              mov eax,00000001
[00000d1c](01)  5d                      pop ebp
[00000d1d](01)  c3                      ret
Size in bytes:(0034) [00000d1d]

In order for D simulated by H to have the same behavior as the
directly executed D(D) H must ignore the instruction at machine
address [00000d07]. *That is an incorrect simulation of D*

H does not ignore that instruction and simulates itself simulating D.
The simulated H outputs its own execution trace of D.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer