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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic
Subject: Re: D correctly simulated by H proved for THREE YEARS --- rewritten
Date: Thu, 13 Jun 2024 07:44:34 -0500
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On 6/13/2024 3:15 AM, Fred. Zwarts wrote:
> Op 12.jun.2024 om 21:53 schreef olcott:
>> On 6/12/2024 2:46 PM, Fred. Zwarts wrote:
>>> Op 12.jun.2024 om 21:20 schreef olcott:
>>>>
>>>> On 5/29/2021 2:26 PM, olcott wrote:
>>>> https://groups.google.com/g/comp.theory/c/dTvIY5NX6b4/m/cHR2ZPgPBAAJ
>>>>
>>>> If that was true then you could provide every step of D correctly
>>>> simulated by H such that D simulated by H reaches its own simulated
>>>> "ret" instruction.
>>>
>>> I said that each H is unable to hit its target, so how could it reach
>>> the "ret" instruction of D? Please, think before you reply.
>>
>> It is a binary choice either D correctly simulated by H can
>> possibly terminate normally by reaching its "ret" instruction
>> or not. Your attempt to twist these words to make it look like
>> there is more than these two possibilities is either ignorant
>> or deceptive.
>>
>
> Please, take some more attention to what I said. Read, then think,
> before you reply.
> I said that H is not able to reach its own "ret" when it is simulating
> itself.
That has always been totally irrelevant.
> So, no disagreement with that. That proves that H misses its
> target. The abort is too early. The target is just some steps further.
> It does not mean that the target is at infinity.
>
The outer H always has one more execution trace to base its halt
status decision on than any of the nested emulations. This means
that unless the outer H aborts its simulation then none of them do.
> It is like an archer who is asked to hit a target twice as far as his
> bow can reach. His bow reaches 50m and the target is at 100m. He misses.
> Then he uses a new bow that reaches 100m, but now the target is at 200m.
> He is able to reach the old target, but again he misses the target for
> the new bow. He can continue with a stronger bow, but if the bow reaches
> further, the target is also further away. But note, the target is never
> at infinity.
Sure just like Zeno's paradox where he "proved" that it is impossible to
cross a ten foot wide room in finite time.
> Similarly, the target of the simulator is never at infinity, but always
> some steps further that the simulation goes. You can make a simulator
> that simulates further, which can reach the target of the old simulator,
> but it is unable to reach its own target. So, there is no infinite
> recursion, but the simulation always misses the target. The simulation
> is never able to simulate itself up to the end. It always aborts
> prematurely.
> So, your claim proves that it is not a good idea to simulate H by
> itself. It will always miss the target.
*As soon as H sees the repeating state it stops*
*As soon as H sees the repeating state it stops*
*As soon as H sees the repeating state it stops*
*If you don't understand the infinite recursion example then*
*You lack the required prerequisite knowledge to understand me*
void Infinite_Recursion(u32 N)
{
Infinite_Recursion(N);
}
int main()
{
H(Infinite_Recursion, (ptr)5);
}
_Infinite_Recursion()
[00001ca3] 55 push ebp
[00001ca4] 8bec mov ebp,esp
[00001ca6] 8b4508 mov eax,[ebp+08]
[00001ca9] 50 push eax
[00001caa] e8f4ffffff call 00001ca3
[00001caf] 83c404 add esp,+04
[00001cb2] 5d pop ebp
[00001cb3] c3 ret
Size in bytes:(0017) [00001cb3]
_main()
[00001e23] 55 push ebp
[00001e24] 8bec mov ebp,esp
[00001e26] 6a05 push +05 ; push 5
[00001e28] 68a31c0000 push 00001ca3 ; push Infinite_Recursion
[00001e2d] e8e1f6ffff call 00001513 ; call H
[00001e32] 83c408 add esp,+08
[00001e35] eb04 jmp 00001e3b
[00001e37] 33c0 xor eax,eax
[00001e39] eb02 jmp 00001e3d
[00001e3b] 33c0 xor eax,eax
[00001e3d] 5d pop ebp
[00001e3e] c3 ret
Size in bytes:(0028) [00001e3e]
machine stack stack machine assembly
address address data code language
======== ======== ======== ========= =============
[00001e23][001031e9][00000000] 55 push ebp
[00001e24][001031e9][00000000] 8bec mov ebp,esp
[00001e26][001031e5][00000005] 6a05 push +05 ; push 5
[00001e28][001031e1][00001ca3] 68a31c0000 push 00001ca3 ; push
Infinite_Recursion
[00001e2d][001031dd][00001e32] e8e1f6ffff call 00001513 ; call H
H: Begin Simulation Execution Trace Stored at:113295
Address_of_H:1513
[00001ca3][00113281][00113285] 55 push ebp
[00001ca4][00113281][00113285] 8bec mov ebp,esp
[00001ca6][00113281][00113285] 8b4508 mov eax,[ebp+08]
[00001ca9][0011327d][00000005] 50 push eax ; push param
[00001caa][00113279][00001caf] e8f4ffffff call 00001ca3 ; call
Infinite_Recursion
[00001ca3][00113275][00113281] 55 push ebp
[00001ca4][00113275][00113281] 8bec mov ebp,esp
[00001ca6][00113275][00113281] 8b4508 mov eax,[ebp+08]
[00001ca9][00113271][00000005] 50 push eax ; push param
[00001caa][0011326d][00001caf] e8f4ffffff call 00001ca3 ; call
Infinite_Recursion
H: Infinite Recursion Detected Simulation Stopped
[00001e32][001031e9][00000000] 83c408 add esp,+08
[00001e35][001031e9][00000000] eb04 jmp 00001e3b
[00001e3b][001031e9][00000000] 33c0 xor eax,eax
[00001e3d][001031ed][00000018] 5d pop ebp
[00001e3e][001031f1][00000000] c3 ret
Number of Instructions Executed(1104) == 16 Pages
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer