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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: D correctly simulated by H proved for THREE YEARS --- simulating
 vs. deciding
Date: Fri, 14 Jun 2024 07:07:52 -0500
Organization: A noiseless patient Spider
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On 6/13/2024 12:38 PM, joes wrote:
> Am Thu, 13 Jun 2024 12:06:08 -0500 schrieb olcott:
>> On 6/13/2024 11:53 AM, joes wrote:
>>> Am Thu, 13 Jun 2024 07:58:27 -0500 schrieb olcott:
>>>> On 6/13/2024 3:52 AM, joes wrote:
>>>>> Am Wed, 12 Jun 2024 18:12:34 -0500 schrieb olcott:
>>>>>> On 6/12/2024 5:59 PM, Richard Damon wrote:
>>>>>>> On 6/12/24 12:50 PM, olcott wrote:
>>>>>>>> On 6/12/2024 6:33 AM, Richard Damon wrote:
>>>>>>>>> On 6/11/24 11:34 PM, olcott wrote:
>>>>>>>>>> On 6/11/2024 9:32 PM, Richard Damon wrote:
>>>>>>>>>>> On 6/11/24 8:57 PM, olcott wrote:
>>>>>>>>>>>> On 6/11/2024 7:20 PM, Python wrote:
>>>>>>>>>>>>> Le 12/06/2024 à 01:23, olcott a écrit :
> 
>>>>>> *If that was true then you could show ALL OF THE DETAILED STEPS*
>>>>>> *of the mapping that H(D,D) computes to derive that behavior*
>>>>> Any UTM/simulator does it. But H must halt, so it's wrong on non-
>>>>> terminating inputs.
>>> A decider must halt. A simulator must have the same behaviour and can't
>>> abort a nonterminating program. A halting decider is impossible.
>>>
>> void Infinite_Recursion(u32 N)
>> {
>>     Infinite_Recursion(N);
>> }
>>
>> In other words you are saying that a simulating termination analyzer
>> that correctly determines that the above Infinite_Recursion cannot
>> possibly halt is WRONG BY DEFINITION?
> Yes, because to give that result it must halt.
> 
>> *THESE PEOPLE WOULD DISAGREE*
>> AProVE: Non-Termination Witnesses for C Programs
> This is not a simulator.
> 

Yes it does you ignorant troll.
Then AProVE symbolically executes the LLVM program

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer