Deutsch English Français Italiano |
<v4i27r$30hok$1@dont-email.me> View for Bookmarking (what is this?) Look up another Usenet article |
Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> Newsgroups: sci.math Subject: Re: how Date: Fri, 14 Jun 2024 11:30:18 -0700 Organization: A noiseless patient Spider Lines: 34 Message-ID: <v4i27r$30hok$1@dont-email.me> References: <qHqKnNhkFFpow5Tl3Eiz12-8JEI@jntp> <hZvnfi5EsOcLQp4jywf9ecNmAW8@jntp> <v4cvqt$1qbpc$3@dont-email.me> <marAIk0bzCCe6m7qluPLtxzZ0Zw@jntp> <v4d1pc$1qq74$2@dont-email.me> <9HunCi0heOernIpLiINDMDau01o@jntp> <v4d2f7$1qq74$5@dont-email.me> <v4d2hd$1qq74$6@dont-email.me> <dVNyc7MMp5G7UOSEcqTzh_UWDPI@jntp> <v4ff6r$2dbap$3@dont-email.me> <5ISO1HfS0t1DlswIafDbi0VJXhM@jntp> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Fri, 14 Jun 2024 20:30:19 +0200 (CEST) Injection-Info: dont-email.me; posting-host="8e5f18a20736c78d4fdceb317c66453f"; logging-data="3163924"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1+Qec2NKN6gDMG3LHWrYnzYFiBVhjtk2fI=" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:bGsxtVCFjCnkdkVePBEvm617Y/Y= In-Reply-To: <5ISO1HfS0t1DlswIafDbi0VJXhM@jntp> Content-Language: en-US Bytes: 2052 On 6/14/2024 1:40 AM, WM wrote: > Le 13/06/2024 à 20:53, "Chris M. Thomasson" a écrit : >> On 6/13/2024 3:48 AM, WM wrote: > >>> Fact is: If we assume the existence of ω at the ordinal line, then >>> something must exist before, either dark numbers or nothing. There is >>> no third alternative. Or can you imagine one? >> >> Let be imagine something that was dark: >> >> A = 1024^42426969 > > Then A^A^A is no longer dark, let alone So, the following sequence is never dark? ________________ A = 0 A = A + 1 = 1 A = A + 1 = 2 A = A + 1 = 3 .... (on and on) ... ________________ Right? >> B = A + 1 >> >> A and B were already in the set of natural numbers, right? > > Of course. Okay.