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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic,comp.ai.philosophy
Subject: Re: H(D,D) cannot even be asked about the behavior of D(D) V3
 ---IGNORING ALL OTHER REPLIES
Date: Sat, 15 Jun 2024 18:30:59 -0500
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On 6/15/2024 6:01 PM, Richard Damon wrote:
> On 6/15/24 5:56 PM, olcott wrote:
>> On 6/15/2024 11:33 AM, Richard Damon wrote:
>>> On 6/15/24 12:22 PM, olcott wrote:
>>>> On 6/13/2024 8:24 PM, Richard Damon wrote:
>>>>  > On 6/13/24 11:32 AM, olcott wrote:
>>>>  >>
>>>>  >> It is contingent upon you to show the exact steps of how H computes
>>>>  >> the mapping from the x86 machine language finite string input to
>>>>  >> H(D,D) using the finite string transformation rules specified by
>>>>  >> the semantics of the x86 programming language that reaches the
>>>>  >> behavior of the directly executed D(D)
>>>>  >>
>>>>  >
>>>>  > Why? I don't claim it can.
>>>>
>>>> The first six steps of this mapping are when instructions
>>>> at the machine address range of [00000cfc] to [00000d06]
>>>> are simulated/executed.
>>>>
>>>> After that the behavior of D correctly simulated by H diverges
>>>> from the behavior of D(D) because the call to H(D,D) by D
>>>> correctly simulated by H cannot possibly return to D.
>>>
>>> Nope, the steps of D correctly simulated by H will EXACTLY match the 
>>> steps of D directly executed, until H just gives up and guesses.
>>>
>>
>> When we can see that D correctly simulated by H cannot possibly
>> reach its simulated final state at machine address [00000d1d]
>> after one recursive simulation and the same applies for 2,3,...N
>> recursive simulations then we can abort the simulated input and
>> correctly report that D correctly simulated by H DOES NOT HALT.
> 
> Nope. Because an aborted simulation doesn't say anything about Halting,
> 

It is the mathematical induction that says this.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer