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From: "Fred. Zwarts" <F.Zwarts@HetNet.nl>
Newsgroups: comp.theory,sci.logic
Subject: Re: D correctly simulated by H proved for THREE YEARS --- rewritten
Date: Sun, 16 Jun 2024 21:08:35 +0200
Organization: A noiseless patient Spider
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Op 16.jun.2024 om 14:37 schreef olcott:
> On 6/16/2024 1:21 AM, Fred. Zwarts wrote:
>> Op 15.jun.2024 om 17:23 schreef olcott:
>>> On 6/15/2024 10:12 AM, Fred. Zwarts wrote:
>>>> Op 15.jun.2024 om 16:48 schreef olcott:
>>>>> On 6/15/2024 9:37 AM, Fred. Zwarts wrote:
>>>>>>
>>>>>> Is this the new definition of "pathological"?
>>>>>
>>>>> *It is the same thing that I have been saying all along*
>>>>>
>>>>> 00   typedef void (*ptr)(); // pointer to void function
>>>>> 01
>>>>> 02   int HH(ptr P, ptr I);
>>>>> 03
>>>>> 04   void DDD(int (*x)())
>>>>> 05   {
>>>>> 06     HH(x, x);
>>>>> 07     return;
>>>>> 08   }
>>>>> 09
>>>>> 10   int main()
>>>>> 11   {
>>>>> 12     HH(DDD,DDD);
>>>>> 13   }
>>>>>
>>>>> Line 12 main()
>>>>>    invokes HH(DDD,DDD); that simulates DDD()
>>>>>
>>>>> *REPEAT UNTIL outer HH aborts*
>>>>>    Line 06 simulated DDD()
>>>>>    invokes simulated HH(DDD,DDD); that simulates DDD()
>>>>>
>>>>> DDD correctly simulated by HH never reaches its own "return"
>>>>> instruction and halts.
>>>>
>>>> So, you agree that you are changing definitions. 
>>>
>>> Not at all. The original definition still applies when it
>>> is made more generic.
>>>
>>> 01       int D(ptr p)
>>> 02       {
>>> 03         int Halt_Status = H(p, p);
>>> 04         if (Halt_Status)
>>> 05           HERE: goto HERE;
>>> 06         return Halt_Status;
>>> 07       }
>>>
>>> D correctly simulated by H has isomorphic behavior to DDD
>>> correctly simulated by HH, both get stuck in recursive
>>> simulation.
>>>
>>
>> When asked what is a pathological program olcott replied:
>> Op 14.jun.2024 om 21:18 schreef olcott:
>>> For any program H that might determine whether programs halt, a
>>> "pathological" program D, called with some input, can pass its own
>>> source and its input to H and then specifically do the opposite of what
>>> H predicts D will do. No H can exist that handles this case. 
>>
>>
>> No he defines a "pathological" program as a program that calls H.
>> All words about doing the opposite of what H predicts, have disappeared.
>> Everyone sees the difference, but he is stuck is rebuttal mode and 
>> denies the change of definition.
>>
> 
> The code that "does the opposite" was never reachable by
> a simulating halt decider thus does not change the problem
> for a simulating halt decider when this code is removed.

So, there was never a relation with the Linz proof, where the part that 
does the opposite of what H predicts plays the essential role.

What remains is the fact that H is unable to simulate itself up to its 
final state, which is called a "pathological" property of H.