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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: H(D,D) cannot even be asked about the behavior of D(D) V3 ---IGNORING ALL OTHER REPLIES
Date: Tue, 18 Jun 2024 11:03:08 +0300
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On 2024-06-17 13:03:56 +0000, olcott said:

> On 6/17/2024 2:20 AM, Mikko wrote:
>> On 2024-06-16 12:47:09 +0000, olcott said:
>> 
>>> On 6/16/2024 2:53 AM, Mikko wrote:
>>>> On 2024-06-15 16:22:09 +0000, olcott said:
>>>> 
>>>>> On 6/13/2024 8:24 PM, Richard Damon wrote:
>>>>>  > On 6/13/24 11:32 AM, olcott wrote:
>>>>>  >>
>>>>>  >> It is contingent upon you to show the exact steps of how H computes
>>>>>  >> the mapping from the x86 machine language finite string input to
>>>>>  >> H(D,D) using the finite string transformation rules specified by
>>>>>  >> the semantics of the x86 programming language that reaches the
>>>>>  >> behavior of the directly executed D(D)
>>>>>  >>
>>>>>  >
>>>>>  > Why? I don't claim it can.
>>>>> 
>>>>> The first six steps of this mapping are when instructions
>>>>> at the machine address range of [00000cfc] to [00000d06]
>>>>> are simulated/executed.
>>>>> 
>>>>> After that the behavior of D correctly simulated by H diverges
>>>>> from the behavior of D(D) because the call to H(D,D) by D
>>>>> correctly simulated by H cannot possibly return to D.
>>>>> 
>>>>> _D()
>>>>> [00000cfc](01) 55          push ebp
>>>>> [00000cfd](02) 8bec        mov ebp,esp
>>>>> [00000cff](03) 8b4508      mov eax,[ebp+08]
>>>>> [00000d02](01) 50          push eax       ; push D
>>>>> [00000d03](03) 8b4d08      mov ecx,[ebp+08]
>>>>> [00000d06](01) 51          push ecx       ; push D
>>>>> [00000d07](05) e800feffff  call 00000b0c  ; call H
>>>>> [00000d0c](03) 83c408      add esp,+08
>>>>> [00000d0f](02) 85c0        test eax,eax
>>>>> [00000d11](02) 7404        jz 00000d17
>>>>> [00000d13](02) 33c0        xor eax,eax
>>>>> [00000d15](02) eb05        jmp 00000d1c
>>>>> [00000d17](05) b801000000  mov eax,00000001
>>>>> [00000d1c](01) 5d          pop ebp
>>>>> [00000d1d](01) c3          ret
>>>>> Size in bytes:(0034) [00000d1d]
>>>> 
>>>> When you put "V2" or "V3" or something similar on the subject line
>>>> you should tell what is different from the original version.
>>>> 
>>> 
>>> I ask what are the steps
>>> I provide 6 steps and then ask what are the next steps.
>>> I provide all of the steps.
>> 
>> In which version?
>> 
> 
> *This is the simplest possible version*
> 
> void DDD()
> {
>    H0(DDD);
> }
> 
> After six steps of DDD are correctly emulated by H0
> what machine address of DDD would it be at?
> 
> _DDD()
> [00001fd2] 55               push ebp      ; housekeeping
> [00001fd3] 8bec             mov ebp,esp   ; housekeeping
> [00001fd5] 68d21f0000       push 00001fd2 ; push DDD
> [00001fda] e8f3f9ffff       call 000019d2 ; call H0
> [00001fdf] 83c404           add esp,+04   ; housekeeping
> [00001fe2] 5d               pop ebp       ; housekeeping
> [00001fe3] c3               ret           ; return to caller
> Size in bytes:(0018) [00001fe3]

So how is this a difference between the original version and V2 and V3?

-- 
Mikko