Deutsch   English   Français   Italiano  
<v4sull$2f03$1@news.muc.de>

View for Bookmarking (what is this?)
Look up another Usenet article

Path: ...!feeder1.cambriumusenet.nl!feed.tweak.nl!217.73.144.44.MISMATCH!feeder.ecngs.de!ecngs!feeder2.ecngs.de!144.76.237.92.MISMATCH!3.eu.feeder.erje.net!feeder.erje.net!news.szaf.org!news.karotte.org!news.space.net!news.muc.de!.POSTED.news.muc.de!not-for-mail
From: Alan Mackenzie <acm@muc.de>
Newsgroups: comp.theory,sci.logic
Subject: Re: Simulating termination analyzers by dummies --- What does halting mean?
Followup-To: comp.theory
Date: Tue, 18 Jun 2024 21:36:53 -0000 (UTC)
Organization: muc.de e.V.
Message-ID: <v4sull$2f03$1@news.muc.de>
References: <v4oaqu$f9p5$1@dont-email.me>   <v4qe53$a0nm$1@i2pn2.org> <v4qn65$10qh6$1@dont-email.me> <v4qnkf$a0nm$5@i2pn2.org> <v4qpvo$10qh6$2@dont-email.me> <v4qrmd$a0nm$6@i2pn2.org> <v4qrr8$15beg$1@dont-email.me> <v4qsav$a0nn$3@i2pn2.org> <v4qtaa$15gc5$1@dont-email.me> <v4qu3p$a0nm$7@i2pn2.org> <v4quti$15nn8$1@dont-email.me> <v4rrge$bivn$1@i2pn2.org> <v4s1l0$1boeu$6@dont-email.me> <v4seq5$cbcu$1@i2pn2.org> <v4sfuo$1enie$1@dont-email.me> <v4shpp$cbcu$2@i2pn2.org> <v4st0g$1hjnp$1@dont-email.me>
Injection-Date: Tue, 18 Jun 2024 21:36:53 -0000 (UTC)
Injection-Info: news.muc.de; posting-host="news.muc.de:2001:608:1000::2";
	logging-data="80899"; mail-complaints-to="news-admin@muc.de"
User-Agent: tin/2.6.3-20231224 ("Banff") (FreeBSD/14.0-RELEASE-p5 (amd64))
Bytes: 3382
Lines: 57

[ Followup-To: set ]

In comp.theory olcott <polcott333@gmail.com> wrote:
> On 6/18/2024 12:57 PM, joes wrote:
>> Am Tue, 18 Jun 2024 12:25:44 -0500 schrieb olcott:
>>> On 6/18/2024 12:06 PM, joes wrote:
>>> void DDD()
>>> {
>>>     H0(DDD);
>>> }
>>> DDD correctly simulated by any H0 cannot possibly halt.
>>>> DDD halts iff H0 halts.

>> So H0 returns "doesn't halt" to DDD, which then stops running,
>> so H0 should have returned "halts".

> This was three messages ago.
> I had to make sure that you understood that halting
> does not mean stopping for any reason and only includes
> the equivalent of terminating normally.

No.  You're wrong, here.  A turing machine is either running or it's
halted.  There's no third alternative.  If your C programs are not in one
of these two states, they're not equivalent to turing machines.

> DDD correctly emulated by H0 DOES NOT TERMINATE NORMALLY.

There is no concept of "normal" termination in a turing machine.  The
thing is either running or it's halted.

>>> Some TM's loop and thus never stop running, this is classical
>>> non-halting behavior. UTM's simulate Turing machine descriptions.
>>> This is the same thing as an interpreter interpreting the source-code of
>>> a program.
>> Some TMs do not loop and do not halt.

>>> A UTM can be adapted so that it only simulates a fixed number of
>>> iterations of an input that loops.

As has often been said, it is then no longer a universal turing machine.

>>> When this UTM stops simulating this Turing machine description we
>>> cannot correctly say that this looping input halted.

Yes, we can.  It has been designed to count to 42 then halt.  It is then
in the halted state.

>> Yes. We also cannot say that that input was simulated correctly.

Indeed, not.

> -- 
> Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
> hits a target no one else can see." Arthur Schopenhauer

-- 
Alan Mackenzie (Nuremberg, Germany).