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From: Ross Clark <benlizro@ihug.co.nz>
Newsgroups: sci.lang,soc.culture.german
Subject: =?UTF-8?Q?Re:_Kommen_drei_Logiker_in_eine_Bar._Der_Kellner_fragt:_?=
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Date: Sun, 23 Jun 2024 23:56:07 +1200
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On 23/06/2024 10:39 p.m., Phil Carmody wrote:
> Ruud Harmsen <rh@rudhar.com> writes:
>> Sat, 22 Jun 2024 19:29:14 +0300: Phil Carmody <pc+usenet@asdf.org>
>> scribeva:
>>
>>> Ruud Harmsen <rh@rudhar.com> writes:
>>>> Mon, 17 Jun 2024 11:18:24 -0700: HenHanna <HenHanna@devnull.tb>
>>>> scribeva:
>>>>
>>>>>
>>>>> Kommen drei Logiker in eine Bar. Der Kellner fragt: "Na, was darfs sein,
>>>>> die Herren? Drei Bier?" Sagt der erste Logiker "Ich weiß nicht", der
>>>>> zweite auch "Ich weiß nicht" und der Dritte sagt "Ja"
>>>>>
>>>>>                      ------ is this funny?   i don't really get it.
>>>>
>>>> 0 | 0 | 1 = 1, in Boolean logic.
>>>
>>> True but irrelevant.
>>>
>>> ~0 & ~0 & 1 = 1 is the boolean logic that applies.
>>
>> What do you mean by ~? Not? How is don't know a not.
> 
> ~ is indeed not.
> 
> Saying "don't know" is the *exclusion* of "no" as a possible state,
> because if "no" was this guy's intention he would have correctly
> answered "no" rather than "don't know".
> 
> Phil
> 

But it also excludes "yes". So is ~1 equivalent to ~0? Why not just ~?