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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic
Subject: Re: DDD correctly emulated by H0 --- Why Lie?
Date: Sun, 23 Jun 2024 17:04:23 -0500
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On 6/23/2024 4:49 PM, Richard Damon wrote:
> On 6/23/24 5:41 PM, olcott wrote:
>> On 6/23/2024 1:20 PM, Richard Damon wrote:
>>> On 6/23/24 9:40 AM, olcott wrote:
>>>> _DDD()
>>>> [00002172] 55               push ebp
>>>> [00002173] 8bec             mov ebp,esp
>>>> [00002175] 6872210000       push 00002172 ; push DDD
>>>> [0000217a] e853f4ffff       call 000015d2 ; call HHH0
>>>> [0000217f] 83c404           add esp,+04
>>>> [00002182] 5d               pop ebp
>>>> [00002183] c3               ret
>>>> Size in bytes:(0018) [00002183]
>>>>
>>>> According to the semantics of the x86 programming language
>>>> when DDD correctly emulated by H0 calls H0(DDD) this call
>>>> cannot possibly return.
>>>>
>>>> Likewise according to the semantics of arithmetic for
>>>> decimal integers: 2 + 3 = 5.
>>>>
>>>> Anyone disagreeing with these two statements is WRONG.
>>>>
>>>
>>> NOw, if you REALLY mean just can H0 simulate this input to a final 
>>> state, the answer is WHO CARES.
>>>
>>> But I will put out a few comments on errors in your presentation\.
>>>
>>> First, if you ONLY have the bytes presented, then the answer becomes 
>>> trivial, as H0 HAS to stop emulating when it gets to the call 
>>> instruction, as there is no data at address 000015d2 defined to 
>>> simulate.
>>>
>>
>> What a God damned liar.
>> https://liarparadox.org/HH0_(DDD)_Full_Trace.pdf
>>
> 
> Which begins its trace at main, not DDD:
> 

You knew that there IS an HH0 and lied about it.
That makes you a God damned liar.

Of course C programs begin at main() Liar !!!

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer