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From: efji <efji@efi.efji>
Newsgroups: fr.sci.maths
Subject: =?UTF-8?Q?Re=3A_R=C3=A9solution_du_probl=C3=A8me_pos=C3=A9?=
Date: Tue, 25 Jun 2024 13:47:17 +0200
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Le 25/06/2024 à 13:36, Richard Hachel a écrit :
> Un intervenant posait le problème:
> 
> sqrt(3x+7)+sqrt(x+2)=1
> 
> Soit :
> 
> sqrt(3x+7)=1-sqrt(x+2)
> 
> 3x+7 = 1 -2sqrt(x+2) + (x+2)
> 
> 2x+4 = -2sqrt((x+2)
> 
> x+2= -sqrt(x+2)
> 
> Posons A=(x+2)
> 
> A=-sqrt(A)
> Seule solution possible A=0.
> 
> Soit A=x+2=0
> 
> x=-2

Magnifique :-)

Et le gros malin il fait comment pour résoudre

sqrt(3x+7)+sqrt(x+2)=2

-- 
F.J.