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Path: ...!weretis.net!feeder8.news.weretis.net!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: efji <efji@efi.efji> Newsgroups: fr.sci.maths Subject: =?UTF-8?Q?Re=3A_R=C3=A9solution_du_probl=C3=A8me_pos=C3=A9?= Date: Tue, 25 Jun 2024 13:47:17 +0200 Organization: A noiseless patient Spider Lines: 33 Message-ID: <v5eao5$1hiil$1@dont-email.me> References: <VTMItxncAEYELeWXOtGSe5FrxHU@jntp> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Tue, 25 Jun 2024 13:47:18 +0200 (CEST) Injection-Info: dont-email.me; posting-host="c74765c308b8f28bc5f5bc42990f921b"; logging-data="1624661"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX18AgO0+os9Aeu1z5HsABQ7H" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:O1g5YgfK9v/FEShClFtthUC1Mzg= In-Reply-To: <VTMItxncAEYELeWXOtGSe5FrxHU@jntp> Content-Language: fr, en-US Bytes: 1498 Le 25/06/2024 à 13:36, Richard Hachel a écrit : > Un intervenant posait le problème: > > sqrt(3x+7)+sqrt(x+2)=1 > > Soit : > > sqrt(3x+7)=1-sqrt(x+2) > > 3x+7 = 1 -2sqrt(x+2) + (x+2) > > 2x+4 = -2sqrt((x+2) > > x+2= -sqrt(x+2) > > Posons A=(x+2) > > A=-sqrt(A) > Seule solution possible A=0. > > Soit A=x+2=0 > > x=-2 Magnifique :-) Et le gros malin il fait comment pour résoudre sqrt(3x+7)+sqrt(x+2)=2 -- F.J.