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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory,sci.logic
Subject: Re: DDD correctly emulated by H0 -- Ben agrees that Sipser approved
 criteria is met
Date: Tue, 25 Jun 2024 21:47:35 -0400
Organization: i2pn2 (i2pn.org)
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On 6/25/24 1:45 PM, olcott wrote:
> On 6/25/2024 9:46 AM, Alan Mackenzie wrote:
>> Hi, Ben.
>>
>> Ben Bacarisse <ben@bsb.me.uk> wrote:
>>> Alan Mackenzie <acm@muc.de> writes:
>>
>>>> In comp.theory olcott <polcott333@gmail.com> wrote:
>>>>> On 6/25/2024 4:22 AM, joes wrote:
>>>>>> Am Sat, 22 Jun 2024 13:47:24 -0500 schrieb olcott:
>>>>>>> On 6/22/2024 1:39 PM, Fred. Zwarts wrote:
>>>>>>>> Op 21.jun.2024 om 15:21 schreef olcott:
>>
>>>>>>> When we stipulate that the only measure of a correct emulation is 
>>>>>>> the
>>>>>>> semantics of the x86 programming language then we see that when 
>>>>>>> DDD is
>>>>>>> correctly emulated by H0 that its call to H0(DDD) cannot possibly
>>>>>>> return.
>>>>>> Yes. Which is wrong, because H0 should terminate.
>>
>>>> [ .... ]
>>
>>>>> The call from DDD to H0(DDD) when DDD is correctly emulated
>>>>> by H0 cannot possibly return.
>>
>>>>> Until you acknowledge this is true, this is the
>>>>> only thing that I am willing to talk to you about.
>>
>>>> I think you are talking at cross purposes.  Joes's point is that H0
>>>> should terminate because it's a decider.  You're saying that when H0 is
>>>> "correctly" emulating, it won't terminate.  I don't recall seeing 
>>>> anybody
>>>> arguing against that.
>>
>>>> So you're saying, in effect, H0 is not a decider.  I don't think 
>>>> anybody
>>>> else would argue against that, either.
>>
>>> He's been making exactly the same nonsense argument for years.  It
>>> became crystal clear a little over three years ago when he made the
>>> mistake of posting the pseudo-code for H -- a step by step simulator
>>> that stopped simulating (famously on line 15) when some pattern was
>>> detected.  He declared false (not halting) to be the correct result for
>>> the halting computation H(H_Hat(), H_Hat()) because of what H(H_Hat(),
>>> H_Hat()) would do "if line 15 were commented out"!
>>
>>> PO does occasionally make it clear what the shell game is.
>>
>> I think it's important for (relative) newcomers to the newsgroup to
>> become aware of this.  Each one of them is trying to help PO improve his
>> level of learning.  They will eventually give up, as you and I have
>> done, recognising (as Mike Terry, in particular, has done) that
>> enriching PO's intellect is a quite impossible task.
>>
>> What's the betting he'll respond to this post with his usual short
>> sequence of x86 assembly code together with a demand to recognise
>> something or other as non-terminating?
>>
>>> -- 
>>> Ben.
>>
> 
> <MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>      If simulating halt decider H correctly simulates its input D
>      until H correctly determines that its simulated D would never
>      stop running unless aborted then
> 
>      H can abort its simulation of D and correctly report that D
>      specifies a non-halting sequence of configurations.
> </MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
> 
> On 10/14/2022 7:44 PM, Ben Bacarisse wrote:
>  > I don't think that is the shell game. PO really /has/ an H
>  > (it's trivial to do for this one case) that correctly determines
>  > that P(P) *would* never stop running *unless* aborted.
>  >
>  > He knows and accepts that P(P) actually does stop. The
>  > wrong answer is justified by what would happen if H
>  > (and hence a different P) where not what they actually are.
>  >
> 
> Ben thinks that I tricked professor Sipser into agreeing
> with something that he did not fully understand.
> 
> *The real issue is that no one here sufficiently understands*
> *the highlighted portion of the following definition*
> 
> Computable functions are the formalized analogue of the
> intuitive notion of algorithms, in the sense that a
> function is computable if there exists an algorithm
> that can do the job of the function, i.e.
> 
> *given an input of the function domain*
> *it can return the corresponding output*
> 
> https://en.wikipedia.org/wiki/Computable_function
> 
> 

But only if the function is, in fact, computable.

Since Halting isn't, you can't use that fact.