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From: Richard Damon <richard@damon-family.org>
Newsgroups: comp.theory,sci.logic
Subject: Re: DDD correctly emulated by H0 -- Ben agrees that Sipser approved
 criteria is met
Date: Tue, 25 Jun 2024 22:55:48 -0400
Organization: i2pn2 (i2pn.org)
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On 6/25/24 10:29 PM, olcott wrote:
> On 6/25/2024 9:23 PM, Richard Damon wrote:
>> On 6/25/24 10:05 PM, olcott wrote:
>>> On 6/25/2024 8:47 PM, Richard Damon wrote:
>>>> On 6/25/24 1:45 PM, olcott wrote:
>>>>> On 6/25/2024 9:46 AM, Alan Mackenzie wrote:
>>>>>> Hi, Ben.
>>>>>>
>>>>>> Ben Bacarisse <ben@bsb.me.uk> wrote:
>>>>>>> Alan Mackenzie <acm@muc.de> writes:
>>>>>>
>>>>>>>> In comp.theory olcott <polcott333@gmail.com> wrote:
>>>>>>>>> On 6/25/2024 4:22 AM, joes wrote:
>>>>>>>>>> Am Sat, 22 Jun 2024 13:47:24 -0500 schrieb olcott:
>>>>>>>>>>> On 6/22/2024 1:39 PM, Fred. Zwarts wrote:
>>>>>>>>>>>> Op 21.jun.2024 om 15:21 schreef olcott:
>>>>>>
>>>>>>>>>>> When we stipulate that the only measure of a correct 
>>>>>>>>>>> emulation is the
>>>>>>>>>>> semantics of the x86 programming language then we see that 
>>>>>>>>>>> when DDD is
>>>>>>>>>>> correctly emulated by H0 that its call to H0(DDD) cannot 
>>>>>>>>>>> possibly
>>>>>>>>>>> return.
>>>>>>>>>> Yes. Which is wrong, because H0 should terminate.
>>>>>>
>>>>>>>> [ .... ]
>>>>>>
>>>>>>>>> The call from DDD to H0(DDD) when DDD is correctly emulated
>>>>>>>>> by H0 cannot possibly return.
>>>>>>
>>>>>>>>> Until you acknowledge this is true, this is the
>>>>>>>>> only thing that I am willing to talk to you about.
>>>>>>
>>>>>>>> I think you are talking at cross purposes.  Joes's point is that H0
>>>>>>>> should terminate because it's a decider.  You're saying that 
>>>>>>>> when H0 is
>>>>>>>> "correctly" emulating, it won't terminate.  I don't recall 
>>>>>>>> seeing anybody
>>>>>>>> arguing against that.
>>>>>>
>>>>>>>> So you're saying, in effect, H0 is not a decider.  I don't think 
>>>>>>>> anybody
>>>>>>>> else would argue against that, either.
>>>>>>
>>>>>>> He's been making exactly the same nonsense argument for years.  It
>>>>>>> became crystal clear a little over three years ago when he made the
>>>>>>> mistake of posting the pseudo-code for H -- a step by step simulator
>>>>>>> that stopped simulating (famously on line 15) when some pattern was
>>>>>>> detected.  He declared false (not halting) to be the correct 
>>>>>>> result for
>>>>>>> the halting computation H(H_Hat(), H_Hat()) because of what 
>>>>>>> H(H_Hat(),
>>>>>>> H_Hat()) would do "if line 15 were commented out"!
>>>>>>
>>>>>>> PO does occasionally make it clear what the shell game is.
>>>>>>
>>>>>> I think it's important for (relative) newcomers to the newsgroup to
>>>>>> become aware of this.  Each one of them is trying to help PO 
>>>>>> improve his
>>>>>> level of learning.  They will eventually give up, as you and I have
>>>>>> done, recognising (as Mike Terry, in particular, has done) that
>>>>>> enriching PO's intellect is a quite impossible task.
>>>>>>
>>>>>> What's the betting he'll respond to this post with his usual short
>>>>>> sequence of x86 assembly code together with a demand to recognise
>>>>>> something or other as non-terminating?
>>>>>>
>>>>>>> -- 
>>>>>>> Ben.
>>>>>>
>>>>>
>>>>> <MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>>>>>      If simulating halt decider H correctly simulates its input D
>>>>>      until H correctly determines that its simulated D would never
>>>>>      stop running unless aborted then
>>>>>
>>>>>      H can abort its simulation of D and correctly report that D
>>>>>      specifies a non-halting sequence of configurations.
>>>>> </MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>>>>>
>>>>> On 10/14/2022 7:44 PM, Ben Bacarisse wrote:
>>>>>  > I don't think that is the shell game. PO really /has/ an H
>>>>>  > (it's trivial to do for this one case) that correctly determines
>>>>>  > that P(P) *would* never stop running *unless* aborted.
>>>>>  >
>>>>>  > He knows and accepts that P(P) actually does stop. The
>>>>>  > wrong answer is justified by what would happen if H
>>>>>  > (and hence a different P) where not what they actually are.
>>>>>  >
>>>>>
>>>>> Ben thinks that I tricked professor Sipser into agreeing
>>>>> with something that he did not fully understand.
>>>>>
>>>>> *The real issue is that no one here sufficiently understands*
>>>>> *the highlighted portion of the following definition*
>>>>>
>>>>> Computable functions are the formalized analogue of the
>>>>> intuitive notion of algorithms, in the sense that a
>>>>> function is computable if there exists an algorithm
>>>>> that can do the job of the function, i.e.
>>>>>
>>>>> *given an input of the function domain*
>>>>> *it can return the corresponding output*
>>>>>
>>>>> https://en.wikipedia.org/wiki/Computable_function
>>>>>
>>>>>
>>>>
>>>> But only if the function is, in fact, computable.
>>>>
>>>> Since Halting isn't, you can't use that fact.
>>>
>>> If I ask you: What time is it?
>>> and you do not tell me the answer to the question hidden
>>> in my mind "What did you have for dinner?" We cannot say
>>> that you provided the wrong answer when you tell me what
>>> time it is.
>>
>> Because I answered the actual question.
>>
>> Just like the "Halt Decider" needs to answer the "Halt Decider 
>> Question" and not answer about POOP.
>>
>>>
>>> When we ask H to tell us whether its actual input halts
>>> H can only answer that P correctly simulated by H will not halt.
>>> H cannot answer the question hidden in your mind.
>>>
>>
>> Then you are just admitting that it can't be a Halt Decider.
>>
>> If it isn't what the definition requires, it just isn't one.
>>
> 
> Yes and everyone knows that computer scientists are much
> more infallible than God thus cannot possibly ever make
> a definition that is incoherent in ways that these 100%
> infallible computer scientists never noticed.
>

Except you can't show that the definition IS incoherent, just that *YOU* 
can't understand it.

That is YOUR problem, not the problem of the definition.