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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory,sci.logic
Subject: Re: DDD correctly emulated by H0 -- Ben agrees that Sipser approved
 criteria is met
Date: Wed, 26 Jun 2024 21:13:53 -0500
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On 6/26/2024 8:52 PM, Richard Damon wrote:
> On 6/26/24 9:30 PM, Mike Terry wrote:
>> On 27/06/2024 02:15, Mike Terry wrote:
>>> On 27/06/2024 01:42, Richard Damon wrote:
>>>> On 6/26/24 8:20 PM, olcott wrote:
>>>>> On 6/26/2024 6:55 PM, Richard Damon wrote:
>>>>>> On 6/26/24 7:46 PM, olcott wrote:
>>>>>>> On 6/26/2024 6:41 PM, Richard Damon wrote:
>>>>>>>> On 6/26/24 9:42 AM, olcott wrote:
>>>>>>>>> On 6/26/2024 6:02 AM, Richard Damon wrote:
>>>>>>>>>> On 6/25/24 11:42 PM, olcott wrote:
>>>>>>>>>>>
>>>>>>>>>>> That is not the way that it actually works.
>>>>>>>>>>> That the the way that lies are defined.
>>>>>>>>>>
>>>>>>>>>> Source for you claim?
>>>>>>>>>>
>>>>>>>>>> Where is you finite set of steps from the truthmakers of the 
>>>>>>>>>> system to that claim?
>>>>>>>>>>
>>>>>>>>>
>>>>>>>>> _DDD()
>>>>>>>>> [00002172] 55               push ebp      ; housekeeping
>>>>>>>>> [00002173] 8bec             mov ebp,esp   ; housekeeping
>>>>>>>>> [00002175] 6872210000       push 00002172 ; push DDD
>>>>>>>>> [0000217a] e853f4ffff       call 000015d2 ; call H0(DDD)
>>>>>>>>> [0000217f] 83c404           add esp,+04
>>>>>>>>> [00002182] 5d               pop ebp
>>>>>>>>> [00002183] c3               ret
>>>>>>>>> Size in bytes:(0018) [00002183]
>>>>>>>>>
>>>>>>>>> The call from DDD to H0(DDD) when DDD is correctly emulated
>>>>>>>>> by H0 cannot possibly return.
>>>>>>>>
>>>>>>>> Sure it can. I have shown an H0 that does so.
>>>>>>>>
>>>>>>>
>>>>>>> I already told you that example does not count.
>>>>>>>
>>>>>>> I can't keep repeating those details or others
>>>>>>> that so far have no idea what an x86 emulator is
>>>>>>> will be baffled beyond all hope of comprehension.
>>>>>>>
>>>>>>
>>>>>> WHy not?
>>>>>>
>>>>>
>>>>> We have already been over that you know that you cheated.
>>>>>
>>>>
>>>> Nope, since you didn't put in the rule, and if you had it would have 
>>>> shown that you lied, as if H0 is a pure function then the call to H0 
>>>> emulated by H0 needs to have the same behaivor as the direct call to 
>>>> H0 by main.
>>>
>>> Incidentally, the nonconformance you're referring to is shown 
>>> explicitly in the "195 page trace" that PO linked to.  [I.e. the 
>>> simulated H does not correctly track the code path of the outer H.]
>>
>> I suppose I should have made clear, that's not simply due to the 
>> simulated H being aborted.  There is an instruction in H:   [actually, 
>> in Init_Halts_HH()]
>>
>> [000012e4] 753b jnz 00001321
>>
>> and in outer H control proceeds to 000012e6  [i.e. branch not taken],
>> whilein simulated H control proceeds to 00001321  [i.e. branch taken]
>>
>>
>> Mike.
>>
> 
> Would need to look closer at the code, but I bet that the simulated 
> machine is looking into the trace buffer to see if it is simulated or not.
> 
> In effect, it is misusing static memory just like he says isn't allowed.
> 
> 

The slaves to a UTM either use a portion of the UTMs tape
or they can't possibly exist. There is probably a more pure
way to encode this.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer