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From: joes <noreply@example.com>
Newsgroups: comp.theory
Subject: Re: 197 page execution trace of DDD correctly simulated by HHH
Date: Fri, 28 Jun 2024 19:18:41 -0000 (UTC)
Organization: i2pn2 (i2pn.org)
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Am Fri, 28 Jun 2024 12:53:46 -0500 schrieb olcott:
> On 6/28/2024 12:41 PM, joes wrote:
>> Thanks for leaving the unanswered questions in place, though I’d rather
>> have you answer them.
I rest my case.
>> Am Fri, 28 Jun 2024 12:05:18 -0500 schrieb olcott:
>>> On 6/28/2024 11:26 AM, joes wrote:
>>>> Am Fri, 28 Jun 2024 10:25:36 -0500 schrieb olcott:
>>>>> On 6/28/2024 8:14 AM, joes wrote:
>>>>>> Am Thu, 27 Jun 2024 12:30:38 -0500 schrieb olcott:
>>>>>> To the caller DDD, which then returns to its own caller H0, which
>>>>>> returns „halting” to main… hold on.
Why doesn’t the first recursive H return?
>>>>>> H0 must not report on itself, only on DDD. Which you’ve proven
>>>>>> halts.
>>>>>> We don’t care how H0 deviates (i.e. is incorrect) in its
>>>>>> simulation. That would be main {H0(H0(DDD))}.
Can you see the difference?
>>>>> The behavior of the directly executed DDD() is irrelevant because
>>>>> that is not the behavior of the input.
What is the input?
>>>>> In this case the sequence is the line-by-line execution trace of the
>>>>> behavior of DDD correctly emulated by HHH.
>>>> No, the sequence is the behaviour of DDD, period.
>> The input is not HHH(DDD). See above.
>>>>> The behavior of this input must include and cannot ignore the
>>>>> recursive emulation specified by the fact that DDD is calling its
>>>>> own emulator.
>>>> Yes, and the behaviour of H0 is that it produces the exact same
>>>> behaviour as DDD.
>>> The call from DDD to HHH(DDD) when N steps of DDD are correctly
>>> emulated by any pure function x86 emulator HHH cannot possibly return.
>>> That you assume that it does against the facts is ridiculous.
>> I don’t. A simulator doesn’t even need to return. That’s not in
>> question. A decider however must.
> That you keep trying to ignore the fact that DDD calls HHH(DDD)
> in recursive simulation is your huge mistake.
WTF? I just agreed with you.
Please reply to my other points.
--
Am Fri, 21 Jun 2024 12:22:04 -0500 schrieb olcott: the logical
impossibility of specifying a halt decider H that correctly reports the
halt status of input D that is defined to do the opposite of whatever
value that H reports.