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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: sci.physics.relativity
Subject: Re: In relativity "s" is for "spin"
Date: Sat, 29 Jun 2024 11:45:37 +0300
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On 2024-06-28 18:29:02 +0000, LaurenceClarkCrossen said:

> In relativity "s" is for "spin"
> 
> For everyone's edification, I hereby share relativity explaining how
> light is affected twice as much as everything else, flouting Galileo &
> Eotvos.
> 
> "Are Photons Massless or Massive?"
> 
> = "Since the photon is a spin-1 particle, according to this new
> equation, Eg^2= s^2p^2c^2 + mi^2c^4 , it follows that, s = 2 , for the
> photon. In Section 10, it will become clear when we analysis the motion
> of star light (electromagnetic waves) that this fact that for a photon
> we must have, s = 2 , if Newtonian gravitation is to stand-up to the
> eclipse measurements of the Solar gravitational bending of star light.
> This fact on its it own—i.e., the fact that for a photon we must have, s
> = 2 ; explains the missing factor “2” in the gravitational bending of
> light angle in Newtonian gravitation. We take this as a notable
> achievement of the theory of the Curved Spacetime Dirac Equations
> presented in the readings [14]-[16], in that this theory has been able
> to furnish a missing piece of a great puzzle. It is an achievement in
> much the same way that Professor Paul Dirac [17] [18]’s equation
> furnished the puzzle of the gyromagnetic ratio of the electron (see e.g.
> [16] on how the Dirac equation solved the
> gyromagnetic ratio of the electron)."

Relativity is a theory about nature. It does not define language conventions
such as meaning of "s". Spin is a quantum mechanical concept that is not
relevant to most of relativity.

-- 
Mikko