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From: "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com>
Newsgroups: sci.math
Subject: Re: Does the number of nines increase?
Date: Mon, 1 Jul 2024 11:00:27 -0700
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On 7/1/2024 10:24 AM, Moebius wrote:
> Am 01.07.2024 um 18:37 schrieb Chris M. Thomasson:
>> On 7/1/2024 9:15 AM, WM wrote:
>>> Le 30/06/2024 à 20:45, Moebius a écrit :
>>>> Am 25.06.2024 um 22:18 schrieb WM:
>>>>
>>>>> Let the infinite sequence 0.999...
>>>>
>>>> 0.999... ist keine "infinite sequence", sondern eine Zahl,
>>>
>>> Wrong. 0.999... is an abbreviation of ...(((0.9)9)9)... = 0.9, 0.99, 
>>> 0.999, ... converging to but never reaching 1.
>>>
>> .(9) is just <etc.>
> 
> Please don't make the same mistakes as Mückenheim.
> 
> I'm talking about the number 0.999... (i.e. 1) here.

..999... = .(9) = 1

That is just how base 10 can represent one, rather than just 1.

1 = .999... = .(9) = 1

Fair enough?


> Not about the 
> string "0.999..." (consisting of 8 characters) or a "representation" 
> (say the decimal representation) of the number which may be denoted by 
> the string "0.999...", or ".(9)", etc.

Not about storing the individual iterates as in using memory for each 
iterate. We can compute them, and gain a precision, say a fractal needs 
enough nines to render itself.

..0010105599999999

Works, The number of 9's is there, it is a finite view.

..00101055999999999 is a completely different fractal.


> 
> This means especially that 0.999... (i.e. the number 1) is not an 
> "infinite sequence".