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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: 197 page execution trace of DDD correctly simulated by HHH
Date: Mon, 1 Jul 2024 20:36:51 -0500
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On 7/1/2024 7:38 PM, Richard Damon wrote:
> On 7/1/24 8:59 AM, olcott wrote:
>> On 7/1/2024 3:23 AM, Fred. Zwarts wrote:
>>> Op 30.jun.2024 om 19:20 schreef olcott:
>>>>
>>>> _DDD()
>>>> [00002172] 55               push ebp      ; housekeeping
>>>> [00002173] 8bec             mov ebp,esp   ; housekeeping
>>>> [00002175] 6872210000       push 00002172 ; push DDD
>>>> [0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
>>>> [0000217f] 83c404           add esp,+04
>>>> [00002182] 5d               pop ebp
>>>> [00002183] c3               ret
>>>> Size in bytes:(0018) [00002183]
>>>>
>>>
>>> It cannot possibly return, because HHH aborts itself one cycle too 
>>> early, showing that the emulation is incorrect. If that is over your 
>>> head, try to learn how x86 instructions work.
>>
>> _DDD()
>> [00002172] 55               push ebp      ; housekeeping
>> [00002173] 8bec             mov ebp,esp   ; housekeeping
>> [00002175] 6872210000       push 00002172 ; push DDD
>> [0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
>> [0000217f] 83c404           add esp,+04
>> [00002182] 5d               pop ebp
>> [00002183] c3               ret
>> Size in bytes:(0018) [00002183]
>>
>> DDD is correctly emulated by HHH which calls an
>> emulated HHH(DDD) to repeat the process until aborted.
>>
>>
> 
> CAN'T BE.
> 
> A "Correct Emulation" is one that produces the same result as the 
> program at the input.
> 

Which can only possibly occur be disregarding the semantics
of the x86 language. Liars would do that ignoramuses would do
that. Everyone with the equivalent of a BSCS would know that
what I said is true.


-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer