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From: Richard Damon <richard@damon-family.org>
Newsgroups: sci.math
Subject: Re: How many different unit fractions are lessorequal than all unit
 fractions?
Date: Tue, 10 Sep 2024 21:37:12 -0400
Organization: i2pn2 (i2pn.org)
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On 9/9/24 11:08 AM, WM wrote:
> On 09.09.2024 13:49, joes wrote:
>> Am Mon, 09 Sep 2024 12:27:47 +0200 schrieb WM:
>>> On 08.09.2024 22:11, Richard Damon wrote:
>>>> On 9/8/24 3:48 PM, WM wrote:
>>>
>>>>> Select any gap between one of the first ℵo unit fractions and its
>>>>> neighbour. Call its size x. Then ℵo unit fractions cannot fit into the
>>>>> interval (0, x), independent of the actual size.
>>>> But that is changing the value of x in the middle of the problem which
>>>> isn't allowed.
>>>> Given that new x, we can choose a new set of Aleph_0 unit fractions
>>>> below that x.
>>> ℵo unit fractions are claimed to be smaller than every x > 0. If that is
>>> true then I can choose as the x one of the ℵo intervals between two of
>>> them.
>> More precisely: every positive x has infinitely many smaller unit
>> fractions (mind the quantifier order).
> 
> The quantifier order related to the problem is this: NUF(x) = ℵo means: 
> There exist ℵo unit fractions smaller than any x > 0. If this is not 
> true, then there are fewer. How many unit fractions are smaller than any 
> x > 0. THAT is the question. None. But all are differente. Hence there 
> must be a first one smaller than all other unit fractions. Note that 
> real points are in question. Real points fixed on the real line.

The number of unit fractions smaller than any positive x is Aleph_0. 
PERIOD. They are all diffferent.

That does NOT mean there must be a first, THAT is irrational finite 
thinking, which doesn't work on unbounded sets, and your using it has 
exploded your brain into smithereens by its contradictions.

> 
>  > A number is not an interval.
> 
> An interval has a length that can be expressed by a real number:
> 1/n - 1/(n+1) = x .
> 
> Then the interval (0, x) contains not all unit fractions, for instance 
> not 1/n.

But it contains almost all of them, an Aleph_0 of them while missing 
only a finite number of them.

A set of size Aleph_0 can (repeatedly) loose finite number of elements 
and maintain its size. This fact seems to be beyond your ability to 
understand.


> 
> Regards, WM
>>
>