Deutsch   English   Français   Italiano  
<v6h861$vbi2$1@dont-email.me>

View for Bookmarking (what is this?)
Look up another Usenet article

Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail
From: Mikko <mikko.levanto@iki.fi>
Newsgroups: sci.physics.relativity
Subject: Re: Proper time differences
Date: Mon, 8 Jul 2024 20:38:09 +0300
Organization: -
Lines: 31
Message-ID: <v6h861$vbi2$1@dont-email.me>
References: <time-20240708154438@ram.dialup.fu-berlin.de>
MIME-Version: 1.0
Content-Type: text/plain; charset=utf-8; format=flowed
Content-Transfer-Encoding: 8bit
Injection-Date: Mon, 08 Jul 2024 19:38:10 +0200 (CEST)
Injection-Info: dont-email.me; posting-host="6652ac60aaac016e9d092dfef982db53";
	logging-data="1027650"; mail-complaints-to="abuse@eternal-september.org";	posting-account="U2FsdGVkX1+tNTHIqSxXr3nhPgQllPBu"
User-Agent: Unison/2.2
Cancel-Lock: sha1:Wgue1jTHNkpIEiXwix8kO14YqY4=
Bytes: 1710

On 2024-07-08 14:45:12 +0000, Stefan Ram said:

>   From various sources I gather,
> 
> dt = "gamma" d"tau".

The defining equation of proper duration is

  dτ² = dt² - dx²

which is equivalent to your equatio.

>   Where t is the coordinate time in the rest frame, "gamma"
>   is the Lorentz gamma factor and "tau" is the proper time.
> 
>   Now, if "gamma" is constant, I think we can replace the "d"
>   by "D" (triangle which is flat at its bottom), i.e., we can
>   use finite difference instead of infinitesimal ones:
> 
> Dt = "gamma" D"tau".

That's right. That happens when the moving object is not accelerated.

>   I believe 0<="gamma"<=1, so, for an example, we can assume
>   "gamma" to be 0.5:

No, gamma is 1 / sqrt(1 - v²) which is 1 when v = 0 and greater otherwise.

-- 
Mikko