| Deutsch English Français Italiano |
|
<v6h861$vbi2$1@dont-email.me> View for Bookmarking (what is this?) Look up another Usenet article |
Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: Mikko <mikko.levanto@iki.fi> Newsgroups: sci.physics.relativity Subject: Re: Proper time differences Date: Mon, 8 Jul 2024 20:38:09 +0300 Organization: - Lines: 31 Message-ID: <v6h861$vbi2$1@dont-email.me> References: <time-20240708154438@ram.dialup.fu-berlin.de> MIME-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed Content-Transfer-Encoding: 8bit Injection-Date: Mon, 08 Jul 2024 19:38:10 +0200 (CEST) Injection-Info: dont-email.me; posting-host="6652ac60aaac016e9d092dfef982db53"; logging-data="1027650"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX1+tNTHIqSxXr3nhPgQllPBu" User-Agent: Unison/2.2 Cancel-Lock: sha1:Wgue1jTHNkpIEiXwix8kO14YqY4= Bytes: 1710 On 2024-07-08 14:45:12 +0000, Stefan Ram said: > From various sources I gather, > > dt = "gamma" d"tau". The defining equation of proper duration is dτ² = dt² - dx² which is equivalent to your equatio. > Where t is the coordinate time in the rest frame, "gamma" > is the Lorentz gamma factor and "tau" is the proper time. > > Now, if "gamma" is constant, I think we can replace the "d" > by "D" (triangle which is flat at its bottom), i.e., we can > use finite difference instead of infinitesimal ones: > > Dt = "gamma" D"tau". That's right. That happens when the moving object is not accelerated. > I believe 0<="gamma"<=1, so, for an example, we can assume > "gamma" to be 0.5: No, gamma is 1 / sqrt(1 - v²) which is 1 when v = 0 and greater otherwise. -- Mikko