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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: DDD correctly emulated by HHH cannot possibly halt
Date: Wed, 10 Jul 2024 08:25:54 -0500
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On 7/10/2024 2:02 AM, Mikko wrote:
> On 2024-07-09 23:49:16 +0000, olcott said:
> 
>> _DDD()
>> [00002163] 55         push ebp      ; housekeeping
>> [00002164] 8bec       mov ebp,esp   ; housekeeping
>> [00002166] 6863210000 push 00002163 ; push DDD
>> [0000216b] e853f4ffff call 000015c3 ; call HHH(DDD)
>>
>> DDD correctly emulated by any pure function HHH that
>> correctly emulates 1 to ∞ steps of DDD can't make it
>> past the above line of code no matter what.
>>
>> [00002170] 83c404     add esp,+04
>> [00002173] 5d         pop ebp
>> [00002174] c3         ret
>> Size in bytes:(0018) [00002174]
> 
> The subject line is misleading. There is only one DDD so "DDD correctly
> emulated by HHH" should simply mean DDD and nothing else.

*I added this to my latest paper*

Every time any HHH correctly emulates DDD it calls the
x86utm operating system to create a separate process
context with its own memory virtual registers and stack,
thus each recursively emulated DDD is a different instance.

Simulating Termination Analyzer H is Not Fooled by Pathological Input D
https://www.researchgate.net/publication/369971402_Simulating_Termination_Analyzer_H_is_Not_Fooled_by_Pathological_Input_D 


-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer