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Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail From: "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> Newsgroups: sci.math Subject: Re: Does the number of nines increase? Date: Wed, 10 Jul 2024 21:41:31 -0700 Organization: A noiseless patient Spider Lines: 42 Message-ID: <v6nnpr$2a8a6$1@dont-email.me> References: <tJf9P9dALSN4l2XH5vdqPbXSA7o@jntp> <69d5b220-850b-4faa-b9b4-b25cd74d1666@att.net> <iXwHO-pH72dPrRO8fKLu73u-pDc@jntp> <v6etjs$f608$6@dont-email.me> <rOlUS7lI7QcAQJM95Z2fo8X09x0@jntp> <v6etov$f604$2@dont-email.me> <02WQWLab8x41L6XRW0n7Ba0poZ8@jntp> <v6iaf6$18428$1@dont-email.me> <v6j2cm$1bggk$1@dont-email.me> <v6k5fj$1gsq2$2@dont-email.me> <v6k8rg$1hehh$1@dont-email.me> <v6kacc$1ho2l$1@dont-email.me> <v6kb9f$1hehi$2@dont-email.me> <v6n02q$231iu$3@dont-email.me> <v6n0mu$22nd0$5@dont-email.me> <v6n1q7$22opo$9@dont-email.me> <v6n3gg$22ncv$4@dont-email.me> <v6n3q0$22nd0$9@dont-email.me> <v6n3tb$22nd0$10@dont-email.me> <v6n5hm$2436h$1@dont-email.me> <v6n6bh$23rgt$1@dont-email.me> <87v81cn4xy.fsf@bsb.me.uk> MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8; format=flowed Content-Transfer-Encoding: 7bit Injection-Date: Thu, 11 Jul 2024 06:41:32 +0200 (CEST) Injection-Info: dont-email.me; posting-host="9e4d47bab28597d7f8b7db1375a7cff9"; logging-data="2433350"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX19bY8J5yUc/AbmQaF6dTxjOzqnMEi9OV4s=" User-Agent: Mozilla Thunderbird Cancel-Lock: sha1:YWf89pkhRNsyvZLtIzCtRervt5I= Content-Language: en-US In-Reply-To: <87v81cn4xy.fsf@bsb.me.uk> Bytes: 2729 On 7/10/2024 5:32 PM, Ben Bacarisse wrote: > "Chris M. Thomasson" <chris.m.thomasson.1@gmail.com> writes: [...] Just making up a quick example, I need to work on something else right now... Sorry Ben. aba b ab = ababab aba ba b = ababab Can we try to use something like: a = 2 b = 3 Where: ab ab ab = 2 + 3 + 2 + 3 + 2 + 3 = 15 aba ba b = 2 + 3 + 2 + 3 + 2 + 3 = 15 And/or, using a little sorting: ab ab ab = 2 + 2 + 2 + 3 + 3 + 3 = 15 or: ab ab ab = (2 * 3) + (3 * 3) = 15 aba ba b = 2 * 3 + 3^2 = 15 Reduce to lowest terms. Go on... So, we can take all of the patterns that equal the top and bottom grid "numbers", so to speak, and then work with those that fit the condition instead of comparing actual strings? Sound okay as a possible base for a "solver", or is it crap to the n'th power? If they have the same number, then we can drill down on them? I have to do some 3d work right now. Shit. Now I am thinking of a uniqueness property...