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From: James Kuyper <jameskuyper@alumni.caltech.edu>
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On 11/07/2024 19:25, bart wrote:
> On 11/07/2024 16:58, David Brown wrote:
....
>> You've mentioned very clearly that your understanding of C is a mess.  
>> C itself is quite simple here, 
> 
> Not it isn't. The fact that I can do this:
> 
>      void F(vector a) {}          // typedef byte vector[100];
> 
> and get the type of 'a' as 'byte*', sizeof(a) as 8, sizeof(*a) as 1, but 
> sizeof(vector) as 100, suggests all sorts of shenanigans.

No, just one shenanigan. It suggests that when a function parameter is
declared as an array of 'type', that it is treated as a declaration of a
pointer to that type.

Every fact that you listed above follows from this rule which is very
explicitly stated in the C standard and any C textbook, and which is
simple enough that most C newbies figure it out fairly quickly. It has
already been explained to you hundreds of times over the past decade or
so - but has apparently never actually gotten into your brain

>> and the rules are not hard to understand. 
> 
> Ha ha ha! Of course you would say that. 

Keep in mind that you've proven repeatedly that your ability to
understand even the simplest features of C is quite negligible. The fact
that you can't understand it proves almost nothing about how hard it is
for most people to understand.