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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: DDD correctly emulated by HHH is correctly rejected as
 non-halting V2
Date: Sun, 14 Jul 2024 09:50:47 -0500
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On 7/14/2024 5:09 AM, Mikko wrote:
> On 2024-07-12 14:56:05 +0000, olcott said:
> 
>> We stipulate that the only measure of a correct emulation is the
>> semantics of the x86 programming language.
>>
>> _DDD()
>> [00002163] 55         push ebp      ; housekeeping
>> [00002164] 8bec       mov ebp,esp   ; housekeeping
>> [00002166] 6863210000 push 00002163 ; push DDD
>> [0000216b] e853f4ffff call 000015c3 ; call HHH(DDD)
>> [00002170] 83c404     add esp,+04
>> [00002173] 5d         pop ebp
>> [00002174] c3         ret
>> Size in bytes:(0018) [00002174]
>>
>> When N steps of DDD are emulated by HHH according to the
>> semantics of the x86 language then N steps are emulated correctly.
>>
>> When we examine the infinite set of every HHH/DDD pair such that:
>> HHH₁ one step of DDD is correctly emulated by HHH.
>> HHH₂ two steps of DDD are correctly emulated by HHH.
>> HHH₃ three steps of DDD are correctly emulated by HHH.
>> ...
>> HHH∞ The emulation of DDD by HHH never stops running.
>>
>> The above specifies the infinite set of every HHH/DDD pair
>> where 1 to infinity steps of DDD are correctly emulated by HHH.
> 
> You should use the indices here, too, e.g., "where 1 to infinity steps of
> DDD₁ are correctly emulated by HHH₃" or whatever you mean.
> 

DDD is the exact same fixed constant finite string that
always calls HHH at the same fixed constant machine
address.


-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer