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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: DDD correctly emulated by HHH is Correctly rejected as
 non-halting V2
Date: Sun, 14 Jul 2024 19:30:27 -0500
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On 7/14/2024 7:20 PM, joes wrote:
> Am Sun, 14 Jul 2024 09:00:55 -0500 schrieb olcott:
>> On 7/14/2024 3:29 AM, joes wrote:
>>> Am Sat, 13 Jul 2024 18:33:53 -0500 schrieb olcott:
>>>> On 7/13/2024 6:26 PM, joes wrote:
>>>>> Can you elaborate? All runtime instances share the same static code.
>>>>> I am talking about the inner HHH which is called by the simulated
>>>>> DDD. That one is, according to you, aborted. Which is wrong, because
>>>>> by virtue of running the same code, the inner HHH aborts ITS
>>>>> simulation of DDD calling another HHH.
> 
>>> What are the twins and what is their difference?
>>> Do you disagree with my tracing?
> 
> 
>> The directly executed DDD is like the first call of infinite recursion.
>> The emulated DDD is just like the second call of infinite recursion.
>> When the second call of infinite recursion is aborted then the first
>> call halts.
> Not really. Execution does not continue.
>> void Infinite_Recursion()
>> {
>>     Infinite_Recursion();
>> }
>> The above *is* infinite recursion.
>> A program could emulate the above code and simply skip line 3 causing
>> Infinite_Recursion() to halt.
> That would be incorrect.
> 
>> When DDD calls HHH(DDD) HHH returns.
> Therefore it does not need to be aborted.
>> When DDD correctly emulated by HHH the call never returns as is proven
>> below. The executed DDD() has HHH(DDD) skip this call.
> I do not see this below.
>> HHH(DDD) must skip this call itself by terminating the whole DDD
>> process.
> 
>> Because this HHH does not know its own machine address HHH only sees
>> that DDD calls a function that causes its first four steps to be
>> repeated. HHH does not know that this is recursive simulation. To HHH it
>> looks just like infinite recursion.
> 
>> New slave_stack at:1038c4 -- create new process context for 1st DDD
>> Begin Local Halt Decider Simulation   Execution Trace Stored at:1138cc
> 
>> [0000217a][001138b4][0000217f] e853f4ffff call 000015d2 ; call HHH(DDD)
>> New slave_stack at:14e2ec -- create new process context for 2nd DDD
> 
>> [0000217a][0015e2dc][0000217f] e853f4ffff call 000015d2 ; call HHH(DDD)
>> Local Halt Decider: Infinite Recursion Detected Simulation Stopped

> How is this detected? Is it also triggered when calling a function
> in a loop?
> 

You never bothered to answer whether or not you have 100%
understanding of infinite recursion. If you don't then you
can never understand what I am saying. If you do that I
already proved my point. Here is the proof again:

New slave_stack at:1038c4
Begin Local Halt Decider Simulation   Execution Trace Stored at:1138cc
[00002172][001138bc][001138c0] 55         push ebp      ; housekeeping
[00002173][001138bc][001138c0] 8bec       mov ebp,esp   ; housekeeping
[00002175][001138b8][00002172] 6872210000 push 00002172 ; push DDD
[0000217a][001138b4][0000217f] e853f4ffff call 000015d2 ; call HHH(DDD)
New slave_stack at:14e2ec
[00002172][0015e2e4][0015e2e8] 55         push ebp      ; housekeeping
[00002173][0015e2e4][0015e2e8] 8bec       mov ebp,esp   ; housekeeping
[00002175][0015e2e0][00002172] 6872210000 push 00002172 ; push DDD
[0000217a][0015e2dc][0000217f] e853f4ffff call 000015d2 ; call HHH(DDD)
Local Halt Decider: Infinite Recursion Detected Simulation Stopped


-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer