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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: What is the correct halt status for HHH(DDD) ?
Date: Mon, 15 Jul 2024 10:22:28 +0300
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On 2024-07-14 14:36:52 +0000, olcott said:

> On 7/14/2024 3:00 AM, Mikko wrote:
>> On 2024-07-13 18:15:35 +0000, olcott said:
>> 
>>> On 7/13/2024 12:25 PM, Richard Damon wrote:
>>>> On 7/13/24 12:48 PM, olcott wrote:
>>>>> What is the correct halt status for an input to
>>>>> a simulating termination analyzer that calls its
>>>>> own termination analyzer?
>>>>> 
>>>>> typedef void (*ptr)();
>>>>> int HHH(ptr P);
>>>>> 
>>>>> void DDD()
>>>>> {
>>>>>    HHH(DDD);
>>>>> }
>>>>> 
>>>>> int main()
>>>>> {
>>>>>    HHH(DDD);
>>>>> }
>>>>> 
>>>> 
>>>> Halting.
>>>> 
>>>> Since HHH defined to be a termination analyzer, by that definition it 
>>>> must return to its caller.
>>>> 
>>>> Since DDD has no inputs, its behavior isn't affected by any inputs, and 
>>>> thus DDD will halt for ALL input conditions, so
>>> 
>>> You are stupidly saying that Infinite_Loop() will halt because
>>> it has no inputs.
>> 
>>> void Infinite_Loop()
>>> {
>>>    HERE: goto HERE;
>>> }
>> 
>> You are stupidly saying that Infinite loop is executed as a part of HHH.
>> 
> 
> Infinite_Loop() is emulated in its own process context.

In that case, how do you justify "You are stupidly saying"?

-- 
Mikko