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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Who here understands that the last paragraph is Necessarily true?
Date: Tue, 16 Jul 2024 13:26:12 -0500
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On 7/16/2024 3:16 AM, Mikko wrote:
> On 2024-07-15 13:51:14 +0000, olcott said:
> 
>> On 7/15/2024 3:37 AM, Mikko wrote:
>>> On 2024-07-15 03:41:24 +0000, olcott said:
>>>
>>>> On 7/14/2024 9:04 PM, Richard Damon wrote:
>>>>> On 7/14/24 9:27 PM, olcott wrote:
>>>>>>
>>>>>> Any input that must be aborted to prevent the non termination
>>>>>> of simulating termination analyzer HHH necessarily specifies
>>>>>> non-halting behavior or it would never need to be aborted.
>>>>>
>>>>> Excpet, as I have shown, it doesn't.
>>>>>
>>>>> Your problem is you keep on ILEGALLY changing the input in your 
>>>>> argument because you have misdefined what the input is.
>>>>>
>>>>> The input to HHH is ALL of the memory that it would be accessed in 
>>>>> a correct simulation of DDD, which includes all the codd of HHH, 
>>>>> and thus, if you change HHH you get a different input.
>>>>>
>>>>> If you want to try to claim the input is just the bytes of the 
>>>>> function DDD proper then you are just admitting that you are 
>>>>> nothing more than a lying idiot that doesn't understand the problem,
>>>> Turing machines only operate on finite strings they do
>>>> not operate on other Turing machines *dumbo*
>>>
>>> That's right. But the finite string can be a description of a Turing 
>>> machine.
>>
>> No that is wrong. The finite string must encode a Turing machine.
> 
> That you agree does not mean that it is wrong.
> 

Your ignorance that a Turing machine cannot take its own
executing self as an input is no rebuttal what-so-ever.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer