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Path: ...!eternal-september.org!feeder3.eternal-september.org!news.eternal-september.org!.POSTED!not-for-mail
From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: DDD correctly emulated by HHH is correctly rejected as non-halting V2
Date: Wed, 17 Jul 2024 09:52:46 +0300
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On 2024-07-16 18:18:07 +0000, olcott said:

> On 7/16/2024 2:57 AM, Mikko wrote:
>> On 2024-07-15 13:43:34 +0000, olcott said:
>> 
>>> On 7/15/2024 3:17 AM, Mikko wrote:
>>>> On 2024-07-14 14:50:47 +0000, olcott said:
>>>> 
>>>>> On 7/14/2024 5:09 AM, Mikko wrote:
>>>>>> On 2024-07-12 14:56:05 +0000, olcott said:
>>>>>> 
>>>>>>> We stipulate that the only measure of a correct emulation is the
>>>>>>> semantics of the x86 programming language.
>>>>>>> 
>>>>>>> _DDD()
>>>>>>> [00002163] 55         push ebp      ; housekeeping
>>>>>>> [00002164] 8bec       mov ebp,esp   ; housekeeping
>>>>>>> [00002166] 6863210000 push 00002163 ; push DDD
>>>>>>> [0000216b] e853f4ffff call 000015c3 ; call HHH(DDD)
>>>>>>> [00002170] 83c404     add esp,+04
>>>>>>> [00002173] 5d         pop ebp
>>>>>>> [00002174] c3         ret
>>>>>>> Size in bytes:(0018) [00002174]
>>>>>>> 
>>>>>>> When N steps of DDD are emulated by HHH according to the
>>>>>>> semantics of the x86 language then N steps are emulated correctly.
>>>>>>> 
>>>>>>> When we examine the infinite set of every HHH/DDD pair such that:
>>>>>>> HHH₁ one step of DDD is correctly emulated by HHH.
>>>>>>> HHH₂ two steps of DDD are correctly emulated by HHH.
>>>>>>> HHH₃ three steps of DDD are correctly emulated by HHH.
>>>>>>> ...
>>>>>>> HHH∞ The emulation of DDD by HHH never stops running.
>>>>>>> 
>>>>>>> The above specifies the infinite set of every HHH/DDD pair
>>>>>>> where 1 to infinity steps of DDD are correctly emulated by HHH.
>>>>>> 
>>>>>> You should use the indices here, too, e.g., "where 1 to infinity steps of
>>>>>> DDD₁ are correctly emulated by HHH₃" or whatever you mean.
>>>>>> 
>>>>> 
>>>>> DDD is the exact same fixed constant finite string that
>>>>> always calls HHH at the same fixed constant machine
>>>>> address.
>>>> 
>>>> If the function called by DDD is not part of the input then the input does
>>>> not specify a behaviour and the question whether DDD halts is ill-posed.
>>>> 
>>> 
>>> We don't care about whether HHH halts. We know that
>>> HHH halts or fails to meet its design spec.
>>> 
>>> We are only seeing if DDD correctly emulated by HHH
>>> can can possibly reach its own final state.
>> 
>> HHH does not see even that. It only sees whther that it does not emulate
>> DDD to its final state.
> 
> No. HHH is not judging whether or not itself is a correct
> emulator. The semantics of the x86 instructions that emulates
> prove that its emulation is correct.

The semantics does not prove. Only a proof would prove.

-- 
Mikko