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Date: Thu, 18 Jul 2024 08:09:42 +0200
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Am 17.07.2024 um 23:20 schrieb WM:

> The question is: How does NUF(x) [jump] from 0 to more? There is a 
> point [namely x = 0] where NUF(x) is 0 and then it [jumps]. How?

Hint:   NUF(x) := |{u e {1/n : n e IN} : u <= x}| (x e IR) .

Hence
         NUF(x) = 0   for all x e IR, x <= 0
and
         NUF(x) = aleph_0   for all x e IR, x > 0 .


That's "how", Du dummer Spinner.