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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: Who here understands that the last paragraph is Necessarily true?
Date: Fri, 19 Jul 2024 12:02:13 +0300
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On 2024-07-16 18:26:12 +0000, olcott said:

> On 7/16/2024 3:16 AM, Mikko wrote:
>> On 2024-07-15 13:51:14 +0000, olcott said:
>> 
>>> On 7/15/2024 3:37 AM, Mikko wrote:
>>>> On 2024-07-15 03:41:24 +0000, olcott said:
>>>> 
>>>>> On 7/14/2024 9:04 PM, Richard Damon wrote:
>>>>>> On 7/14/24 9:27 PM, olcott wrote:
>>>>>>> 
>>>>>>> Any input that must be aborted to prevent the non termination
>>>>>>> of simulating termination analyzer HHH necessarily specifies
>>>>>>> non-halting behavior or it would never need to be aborted.
>>>>>> 
>>>>>> Excpet, as I have shown, it doesn't.
>>>>>> 
>>>>>> Your problem is you keep on ILEGALLY changing the input in your 
>>>>>> argument because you have misdefined what the input is.
>>>>>> 
>>>>>> The input to HHH is ALL of the memory that it would be accessed in a 
>>>>>> correct simulation of DDD, which includes all the codd of HHH, and 
>>>>>> thus, if you change HHH you get a different input.
>>>>>> 
>>>>>> If you want to try to claim the input is just the bytes of the function 
>>>>>> DDD proper then you are just admitting that you are nothing more than a 
>>>>>> lying idiot that doesn't understand the problem,
>>>>> Turing machines only operate on finite strings they do
>>>>> not operate on other Turing machines *dumbo*
>>>> 
>>>> That's right. But the finite string can be a description of a Turing machine.
>>> 
>>> No that is wrong. The finite string must encode a Turing machine.
>> 
>> That you agree does not mean that it is wrong.
>> 
> 
> Your ignorance that a Turing machine cannot take its own
> executing self as an input is no rebuttal what-so-ever.

You should not assume that everyone is as stupid as you.

-- 
Mikko