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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Hypothetical possibilities
Date: Sat, 20 Jul 2024 18:06:36 -0500
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On 7/20/2024 6:00 PM, Richard Damon wrote:
> On 7/20/24 6:47 PM, olcott wrote:
>> On 7/20/2024 5:11 PM, Richard Damon wrote:
>>> On 7/20/24 5:21 PM, olcott wrote:
>>>> On 7/20/2024 4:06 PM, joes wrote:
>>>>> Am Sat, 20 Jul 2024 15:05:53 -0500 schrieb olcott:
>>>>>> On 7/20/2024 2:50 PM, Richard Damon wrote:
>>>>>>> On 7/20/24 3:09 PM, olcott wrote:
>>>>>>>> On 7/20/2024 2:00 PM, Fred. Zwarts wrote:
>>>>>>>>> Op 20.jul.2024 om 17:28 schreef olcott:
>>>>>
>>>>>>>>>> (a) Termination Analyzers / Partial Halt Deciders must halt 
>>>>>>>>>> this is
>>>>>>>>>> a design requirement.
>>>>>>>>>> (b) Every simulating termination analyzer HHH either aborts the
>>>>>>>>>> simulation of its input or not.
>>>>>>>>>> (c) Within the hypothetical case where HHH does not abort the
>>>>>>>>>> simulation of its input {HHH, emulated DDD and executed DDD}
>>>>>>>>>> never stop running.
>>>>>>>>>> This violates the design requirement of (a) therefore HHH must 
>>>>>>>>>> abort
>>>>>>>>>> the simulation of its input.
>>>>> You missed a couple details:
>>>>> A terminating input shouldn't be aborted, or at least not classified
>>>>> as not terminating. Terminating inputs needn't be aborted; they and 
>>>>> the
>>>>> simulator halt on their own.
>>>>>
>>>>>>>>> And when it aborts, the simulation is incorrect. When HHH 
>>>>>>>>> aborts and
>>>>>>>>> halts, it is not needed to abort its simulation, because it 
>>>>>>>>> will halt
>>>>>>>>> of its own.
>>>>>>>> So you are trying to get away with saying that no HHH ever needs to
>>>>>>>> abort the simulation of its input and HHH will stop running?
>>>>> Pretty much.
>>>>>>> It is the fact that HHH DOES abort its simulation that makes it not
>>>>>>> need to.
>>>>>> No stupid it is not a fact that every HHH that can possibly exist 
>>>>>> aborts
>>>>>> its simulation.
>>>>> I thought they all halt after a finite number of steps?
>>>>>
>>>>
>>>> void DDD()
>>>> {
>>>>     HHH(DDD);
>>>>     return;
>>>> }
>>>>
>>>> DDD correctly simulated by pure function HHH cannot
>>>> possibly reach its own return instruction.
>>>>
>>>
>>> Wrong.
>>>
>>
>> You know that you are lying about this as you admit below:
> 
> Nope, YOU just don't what the words mean, and reckless disregard the 
> teaching you have been getting, which makes your errors not just honest 
> mistakes but reckless pathological lies.
> 
>>
>>> It may be that the simulation by HHH never reaches that point, 
>>
>>> but if HHH aborts its simuliaton and returns (as required for it to 
>>> be a decider) then the behavior of DDD 
>>
>> Simulated by HHH is to Die, stop running, no longer function.
> 
> Nope, HHH is NOT the "Machine" that determines what the code does, so 
> can not "Kill" it.
> 

So you are trying to get away with the lie
that an aborted simulation keeps on running.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer