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From: Mikko <mikko.levanto@iki.fi>
Newsgroups: comp.theory
Subject: Re: Who here understands that the last paragraph is Necessarily true?
Date: Sun, 21 Jul 2024 12:57:22 +0300
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On 2024-07-20 14:54:54 +0000, olcott said:

> On 7/20/2024 4:39 AM, Mikko wrote:
>> On 2024-07-19 14:43:53 +0000, olcott said:
>> 
>>> On 7/19/2024 4:02 AM, Mikko wrote:
>>>> On 2024-07-16 18:26:12 +0000, olcott said:
>>>> 
>>>>> On 7/16/2024 3:16 AM, Mikko wrote:
>>>>>> On 2024-07-15 13:51:14 +0000, olcott said:
>>>>>> 
>>>>>>> On 7/15/2024 3:37 AM, Mikko wrote:
>>>>>>>> On 2024-07-15 03:41:24 +0000, olcott said:
>>>>>>>> 
>>>>>>>>> On 7/14/2024 9:04 PM, Richard Damon wrote:
>>>>>>>>>> On 7/14/24 9:27 PM, olcott wrote:
>>>>>>>>>>> 
>>>>>>>>>>> Any input that must be aborted to prevent the non termination
>>>>>>>>>>> of simulating termination analyzer HHH necessarily specifies
>>>>>>>>>>> non-halting behavior or it would never need to be aborted.
>>>>>>>>>> 
>>>>>>>>>> Excpet, as I have shown, it doesn't.
>>>>>>>>>> 
>>>>>>>>>> Your problem is you keep on ILEGALLY changing the input in your 
>>>>>>>>>> argument because you have misdefined what the input is.
>>>>>>>>>> 
>>>>>>>>>> The input to HHH is ALL of the memory that it would be accessed in a 
>>>>>>>>>> correct simulation of DDD, which includes all the codd of HHH, and 
>>>>>>>>>> thus, if you change HHH you get a different input.
>>>>>>>>>> 
>>>>>>>>>> If you want to try to claim the input is just the bytes of the function 
>>>>>>>>>> DDD proper then you are just admitting that you are nothing more than a 
>>>>>>>>>> lying idiot that doesn't understand the problem,
>>>>>>>>> Turing machines only operate on finite strings they do
>>>>>>>>> not operate on other Turing machines *dumbo*
>>>>>>>> 
>>>>>>>> That's right. But the finite string can be a description of a Turing machine.
>>>>>>> 
>>>>>>> No that is wrong. The finite string must encode a Turing machine.
>>>>>> 
>>>>>> That you agree does not mean that it is wrong.
>>>>>> 
>>>>> 
>>>>> Your ignorance that a Turing machine cannot take its own
>>>>> executing self as an input is no rebuttal what-so-ever.
>>>> 
>>>> You should not assume that everyone is as stupid as you.
>>>> 
>>> 
>>> That all rebuttals to my work have one fatal flaw or
>>> another is beyond the comprehension of my reviewers
>>> provides zero evidence that these rebuttals are not flawed.
>> 
>> You can claim that the indications of flaws of your "work" are flawed
>> but that does not remove the indicated flaws from your work.
>> 
> 
> Every rebuttal of my work denies a tautology
> proving that the rebuttal is incorrect because
> all tautologies are necessarily true.
> 
> int main()
> {
>    DDD();
> }
> 
> Calls HHH(DDD) that must abort the emulation of its input
> or {HHH, emulated DDD and executed DDD} never stop running.
> 
> *The above is a Tautology*

No, it is not. The code of DDD is not included so it it is not even
determinable, let alone a tautology, what HHH(DDD) can or should do.

-- 
Mikko