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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Infinite set of HHH/DDD pairs --- truisms
Date: Mon, 22 Jul 2024 14:57:21 -0500
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On 7/22/2024 2:30 PM, Fred. Zwarts wrote:
> Op 22.jul.2024 om 20:31 schreef olcott:
>> On 7/22/2024 12:45 PM, Fred. Zwarts wrote:
>>> Op 22.jul.2024 om 17:08 schreef olcott:
>>>> On 7/22/2024 9:32 AM, joes wrote:
>>>>> Am Mon, 22 Jul 2024 09:13:33 -0500 schrieb olcott:
>>>>>> On 7/22/2024 3:01 AM, Mikko wrote:
>>>>>>> On 2024-07-21 13:50:17 +0000, olcott said:
>>>>>>>> On 7/21/2024 4:38 AM, Mikko wrote:
>>>>>>>>> On 2024-07-20 13:28:36 +0000, olcott said:
>>>>>>>>>> On 7/20/2024 3:54 AM, Mikko wrote:
>>>>>>>>>>> On 2024-07-19 14:39:25 +0000, olcott said:
>>>>>>>>>>>> On 7/19/2024 3:51 AM, Mikko wrote:
>>>>>
>>>>>>>>>>> Anyway you did not say that some HHHᵢ can simulate the
>>>>>>>>>>> corresponding DDDᵢ to its termination. And each DDDᵢ does
>>>>>>>>>>> terminate, whether simulated or not.
>>>>>
>>>>>
>>>>>>>> Then DDD correctly simulated by any pure function HHH cannot 
>>>>>>>> possibly
>>>>>>>> reach its own return instruction and halt, therefore every HHH is
>>>>>>>> correct to reject its DDD as non-halting.
>>>>>>> That does not follow. It is never correct to reject a halting
>>>>>>> comoputation as non-halting.
>>>>>> In each of the above instances DDD never reaches its return 
>>>>>> instruction
>>>>>> and halts. This proves that HHH is correct to report that its DDD 
>>>>>> never
>>>>>> halts.
>>>>> It can't return if the simulation of it is aborted.
>>>>>
>>>>>> Within the hypothetical scenario where DDD is correctly emulated 
>>>>>> by its
>>>>>> HHH and this HHH never aborts its simulation neither DDD nor HHH ever
>>>>>> stops running.
>>>>> In actuality HHH DOES abort simulating.
>>>>>
>>>>>> This conclusively proves that HHH is required to abort the 
>>>>>> simulation of
>>>>>> its corresponding DDD as required by the design spec that every 
>>>>>> partial
>>>>>> halt decider must halt and is otherwise not any kind of decider at 
>>>>>> all.
>>>>> Like Fred recognised a while ago, you are arguing as if HHH didn't 
>>>>> abort.
>>>>>
>>>>>> That HHH is required to abort its simulation of DDD conclusively 
>>>>>> proves
>>>>>> that this DDD never halts.
>>>>> You've got it the wrong way around.
>>>>>
>>>>
>>>> I am talking about hypothetical possible ways that HHH could be 
>>>> encoded.
>>>> (a) HHH(DDD) is encoded to abort its simulation.
>>>> (b) HHH(DDD) is encoded to never abort its simulation.
>>>>
>>>> Therefore (a) is correct and (b) is incorrect according to the
>>>> design requirements for HHH that it must halt.
>>>
>>> Both are incorrect. An HHH, when encoded to abort does not need to be 
>>> aborted when simulated, because it already halts on its own.
>>
>> You must have attention deficit disorder.
>> (a) At least one HHH aborts.
>> (b) No HHH ever aborts.
>>
>> Every X has property Y or not, there is no inbetween.
> 
> Do you have difficulty reading and writing English?
> 
> If every X has property Y or not, then it is clear that every HHH abort 
> or not. 

Sure and when we start a race with a single file line of
people that are 15 feet apart and everyone goes the same
speed then everyone will reach the finish line, eventually.

When the first HHH that reaches the finish line stops
simulating its input then no other HHH can possibly reach
the finish line because nothing is simulating them.

If the first HHH waits on the second HHH and the second
waits on the third... Then no HHH ever aborts.

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer