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From: olcott <polcott333@gmail.com>
Newsgroups: comp.theory
Subject: Re: Infinite set of HHH/DDD pairs --- truisms
Date: Tue, 23 Jul 2024 10:03:11 -0500
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On 7/23/2024 3:17 AM, Fred. Zwarts wrote:
> Op 22.jul.2024 om 21:57 schreef olcott:
>> On 7/22/2024 2:30 PM, Fred. Zwarts wrote:
>>> Op 22.jul.2024 om 20:31 schreef olcott:
>>>> On 7/22/2024 12:45 PM, Fred. Zwarts wrote:
>>>>> Op 22.jul.2024 om 17:08 schreef olcott:
>>>>>> On 7/22/2024 9:32 AM, joes wrote:
>>>>>>> Am Mon, 22 Jul 2024 09:13:33 -0500 schrieb olcott:
>>>>>>>> On 7/22/2024 3:01 AM, Mikko wrote:
>>>>>>>>> On 2024-07-21 13:50:17 +0000, olcott said:
>>>>>>>>>> On 7/21/2024 4:38 AM, Mikko wrote:
>>>>>>>>>>> On 2024-07-20 13:28:36 +0000, olcott said:
>>>>>>>>>>>> On 7/20/2024 3:54 AM, Mikko wrote:
>>>>>>>>>>>>> On 2024-07-19 14:39:25 +0000, olcott said:
>>>>>>>>>>>>>> On 7/19/2024 3:51 AM, Mikko wrote:
>>>>>>>
>>>>>>>>>>>>> Anyway you did not say that some HHHᵢ can simulate the
>>>>>>>>>>>>> corresponding DDDᵢ to its termination. And each DDDᵢ does
>>>>>>>>>>>>> terminate, whether simulated or not.
>>>>>>>
>>>>>>>
>>>>>>>>>> Then DDD correctly simulated by any pure function HHH cannot 
>>>>>>>>>> possibly
>>>>>>>>>> reach its own return instruction and halt, therefore every HHH is
>>>>>>>>>> correct to reject its DDD as non-halting.
>>>>>>>>> That does not follow. It is never correct to reject a halting
>>>>>>>>> comoputation as non-halting.
>>>>>>>> In each of the above instances DDD never reaches its return 
>>>>>>>> instruction
>>>>>>>> and halts. This proves that HHH is correct to report that its 
>>>>>>>> DDD never
>>>>>>>> halts.
>>>>>>> It can't return if the simulation of it is aborted.
>>>>>>>
>>>>>>>> Within the hypothetical scenario where DDD is correctly emulated 
>>>>>>>> by its
>>>>>>>> HHH and this HHH never aborts its simulation neither DDD nor HHH 
>>>>>>>> ever
>>>>>>>> stops running.
>>>>>>> In actuality HHH DOES abort simulating.
>>>>>>>
>>>>>>>> This conclusively proves that HHH is required to abort the 
>>>>>>>> simulation of
>>>>>>>> its corresponding DDD as required by the design spec that every 
>>>>>>>> partial
>>>>>>>> halt decider must halt and is otherwise not any kind of decider 
>>>>>>>> at all.
>>>>>>> Like Fred recognised a while ago, you are arguing as if HHH 
>>>>>>> didn't abort.
>>>>>>>
>>>>>>>> That HHH is required to abort its simulation of DDD conclusively 
>>>>>>>> proves
>>>>>>>> that this DDD never halts.
>>>>>>> You've got it the wrong way around.
>>>>>>>
>>>>>>
>>>>>> I am talking about hypothetical possible ways that HHH could be 
>>>>>> encoded.
>>>>>> (a) HHH(DDD) is encoded to abort its simulation.
>>>>>> (b) HHH(DDD) is encoded to never abort its simulation.
>>>>>>
>>>>>> Therefore (a) is correct and (b) is incorrect according to the
>>>>>> design requirements for HHH that it must halt.
>>>>>
>>>>> Both are incorrect. An HHH, when encoded to abort does not need to 
>>>>> be aborted when simulated, because it already halts on its own.
>>>>
>>>> You must have attention deficit disorder.
>>>> (a) At least one HHH aborts.
>>>> (b) No HHH ever aborts.
>>>>
>>>> Every X has property Y or not, there is no inbetween.
>>>
>>> Do you have difficulty reading and writing English?
>>>
>>> If every X has property Y or not, then it is clear that every HHH 
>>> abort or not. 
>>
>> Sure and when we start a race with a single file line of
>> people that are 15 feet apart and everyone goes the same
>> speed then everyone will reach the finish line, eventually.
>>
>> When the first HHH that reaches the finish line stops
>> simulating its input then no other HHH can possibly reach
>> the finish line because nothing is simulating them.
> 
> Exactly! That is the error in HHH. It stops simulating before the other 
> HHH could reach the finish line. 

So you don't even know how foot races work.

The winner of the race is not supposed to wait
so that everyone crosses the finish line at once.

Also with HHH(DDD) there are infinite instances
in the race. Waiting for the last one to finish
waits forever. The first one to cross the finish
line ends the race. Every other instance is
immediately incapacitated.


> The simulated HHH and the simulating 
> HHH have the same finish line, because both abort after N cycles.
> So, it is ncorrect to abort the simulated HHH, which would have reached 
> the finish line on its own, if not aborted.
> 
>>
>> If the first HHH waits on the second HHH and the second
>> waits on the third... Then no HHH ever aborts.
>>
> Excatly! That is why HHH cannot possibly simulate itself correctly. Do 
> you finally get it?

-- 
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer